Answer:
Wonka bars=3 and Everlasting Gobstoppers=24
Step-by-step explanation:
let the wonka bars be X
and everlasting gobstoppers be Y
the objective is to
maximize 1.3x+3.2y=P
subject to constraints
natural sugar
4x+2y=60------1
sucrose
x+3y=75---------2
x>0, y>0
solving 1 and 2 simultaneously we have
4x+2y=60----1
x+3y=75------2
multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have
4x+2y=60
4x+12y=300
-0-10y=-240
10y=240
y=240/10
y=24
put y=24 in equation 2 we have'
x+3y=75
x+3(24)=75
x+72=75
x=75-72
x=3
put x=3 and y=24 in the objective function we have
maximize 1.3x+3.2y=P
1.3(3)+3.2(24)=P
3.9+76.8=P
80.7=P
P=$80.9
Answer:
3x^2 + 12x + 4y^2 - 8y = 32
Step-by-step explanation:
3(x^2+4x)+4(y^2-2y)=32
At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:
or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32
or, 3x^2 + 12x + 4y^2 - 8y = 32
Since the equation does not have anything to add or deduct, therefore, it is the answer.
Answer:
Job C
Step-by-step explanation:
Since he's paid semi monthly,literally half a month, which is 1125$
Then full month will be 1125×2
Which is 2250
Then annually would be 2250×12=27,000
Answer:
9:3;27:9;87:27
Step-by-step explanation:
The list goes on but hope that answers your question
If A=w(50-w)
A=50w-w^2
dA/dw=50-2w
d2A/dw2=-2
Since the acceleration is a constant negative, that means that when velocity, dA/dw=0, it is at an absolute maximum for A(w)...
dA/d2=0 only when 50=2w, w=25
So as the case with any rectangle, the perfect square will enclose the greatest area possible with respect to a given amount of material to enclose that area...
So the greatest area occurs when W=L=25 in this case:
A(25)=50w-w^2
Area maximum is thus:
Amax=50(25)-(25)^2=625 u^2
