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Triss [41]
2 years ago
13

Consider a parallelogram in which one side is 3 inches long, another side measures 4 inches, and the measurement of one angle is

45°. How many parallelograms can you construct given these conditions? What are the lengths of the sides and the measurements of the angles for the parallelogram(s)?
Complete the steps below to solve the problem.

Part A
Using a ruler and protractor, draw a parallelogram that satisfies the given conditions. (If you don’t have these tools available, draw it freehand.) How many different parallelograms can you draw based on the given conditions?
Mathematics
1 answer:
goldenfox [79]2 years ago
7 0

Answer:

Only one parallelogram can be drawn based on the given conditions.

Step-by-step explanation: just believe me

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Can someone help me with this
Brrunno [24]

Answer:

Step-by-step explanation:

8.) For a triangles sides to make sense, you must be able to add up two values of the triangle, and the result should be more than the third side. Add the lowest values and see if the result is greater than the biggest number:

4.2+7.9=12.1

12.1 is less than the given side, 13.3, so a triangle cannot have the lengths.

10.) 6<x<22

To find the range for the third side of the triangle, you need to find how small x can be (the missing side) and you need to see how large it can be.

You need to see how small it can be because any two sides have to be greater than the third side. You also need to see how big it can be because, if it's too big, the other two sides will be less than the third side, which would make an open shape (see picture).

To find the range, first see how small. Subtract the known sides:

22-6=16

So, x has to be greater than 16.

x > 16

Now add the known sides:

22+6=28

x needs to be less than 28 for the other two sides to be greater than x:

x < 28

Insert the inequalities into a single inequality:

16 < x <28

X has to be greater than x, but less than 28.

4 0
3 years ago
Read 2 more answers
Consider ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.
LenKa [72]

Answer:- B. No, because the corresponding congruent angles listed are not the included angles.


Explanation:-

Given:- ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.

Now, look at the attachment

We can see that ∠X and ∠C are not included angles by the corresponding equal sides.

⇒ We cannot use SAS postulate to show ΔWXY ≅ ΔBCD .

⇒ B is the right option.

SAS postulate tells the if two sides of a triangle and their included angle is equal to the two sides of a triangle and their included angle of another triangle then the two triangles are congruent.

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3 years ago
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ValentinkaMS [17]

Answer:

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Step-by-step explanation:

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At that time, the population is ...

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Simplify. −38+(1+22)2
Hitman42 [59]
It would be 3 over 5
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Identify the vertex of the graph tell weather it is minimum or maximum
Contact [7]

Vertex is (-2,-3) and it's a minimum.

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