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tangare [24]
2 years ago
12

List all the prime factor of 60

Mathematics
2 answers:
Karolina [17]2 years ago
7 0

Answer: 2,3,5

Step-by-step explanation:

the prime factorization of 60 is 2 × 2 × 3 × 5, which can be written as 2 squared × 3 × 5.

ankoles [38]2 years ago
4 0

Answer:

<h2>{2,3,5}</h2><h2 />

Step-by-step explanation:

60÷<u>2</u>=30

30÷<u>2</u>=15

15÷<u>3</u>=5

5÷<u>5</u>=1

There the prime factors of 60 are {2,3,5}

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6)

34, 43, 52, 61, ...

43-34 = 9; 52-43 = 9; 61-52 = 9

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first term:  a = 34

difference:  d = 9

so the formula:

                         a_n=a+d(n-1)\\\\a_n=34+9(n-1)\\\\a_n = 34+9n-9\\\\\underline{a_n=9n+25}

7)

10, 6, 2, -2, ...

6-10 = -4; 2-6 = -4; -2-2 = -4

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 10

difference:  d = -4

so the formula:

                         a_n=a+d(n-1)\\\\a_n=10+(-4)(n-1)\\\\a_n = 10-4n+4\\\\\underline{a_n=-4n+14}

8)

-3, -10, -17, -24, ...

-10-(-3) = -7; -17-(-10) = -7; -24-(-17) = -7

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = -3

difference:  d = -7

so the formula:

                         a_n=a+d(n-1)\\\\a_n=-3+(-7)(n-1)\\\\a_n =-3-4n+7\\\\\underline{a_n=-7n+4}

9)

7, 8.5, 10, 11.5, ...

8.5-7 = 1.5; 10-8.5 = 1.5; 11.5-10 = 1.5

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 7

difference:  d = 1.5

so the formula:

                         a_n=a+d(n-1)\\\\a_n=7+1.5(n-1)\\\\a_n =7+1.5n-1.5\\\\\underline{a_n=1.5n+5.5}

10)

30, 22¹/₂, 15, 7¹/₂, ...

22¹/₂-30 = -7¹/₂;   15-22¹/₂ = -7¹/₂;   7¹/₂-15 = -7¹/₂

The difference between one term and the next is a constant so it is arithmetic sequence

first term:  a = 30

difference:  d = -7¹/₂

so the formula:

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2 years ago
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