Solve for x in the equation x squared minus 10 x + 25 = 35.
2 answers:
Answer:
x = 5 ±
Step-by-step explanation:
Given
x² - 10x + 25 = 35 ( subtract 25 from both sides )
x² - 10x = 10
Using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 5)x + 25 = 10 + 25
(x - 5)² = 35 ( take the square root of both sides )
x - 5 = ± ( add 5 to both sides )
x = 5 ±
That is the second option on list
You might be interested in
Answer: Any real number x as long as and
In other words, anything but 0 or -2/3 is valid.
========================================================
Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.