Answer:
Confidence Interval - 2.290 < S < 2.965
Step-by-step explanation:
Complete question
A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.
Solution
Given
n=50
x=23.33
s=2.6
Alpha = 1-0.80 = 0.20
X^2(a/2,n-1) = X^2(0.10, 49) = 63.17
sqrt(63.17) = 7.948
X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69
sqrt(37.69) = 6.139
s*sqrt(n-1) = 18.2

confidence interval:
(18.2/7.948) < S < (18.2/6.139)
2.290 < S < 2.965
Answer:
Step-by-step explanation:





x ≈ 4.66667
Answer:
There are more cats treats. 504 treats
Step-by-step explanation:
27 boxes of dog biscuits. Each 18 biscuits
27*18=486 biscuits
21 pouches of cat treats. Each 24 treats.
21*24=504
Take the root of both sides, and then solve.
c = sqrt a^2 + b^2, - sqrt a^2 + b^2.
X= a number
If 52 is 130% of a number, then we multiply the unknown number by 130%.
x * 130%= 52
convert % to decimal (130%÷100)
1.3x= 52
divide both sides by 1.3
x= 40
ANSWER: The unknown number is 40, so it is less than 52. We multiply the unknown number by 130% to equal 52.
Hope this helps! :)