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ZanzabumX [31]
3 years ago
11

THE number of bass and pike in a lake are estimated to be in the ratio of 5:3. There are approximately 500 fish in the lake.

Mathematics
1 answer:
lawyer [7]3 years ago
5 0
The bass are 5
and the pike are 3
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David, Chen, and Leslie raised money for the school in a walk-a-thon. Altogether they made $46. Leslie made $10. Chen made twice
Tanzania [10]

Answer:

David made $18

Step-by-step explanation:

Leslie made $10. This means that you take 46-10=36

Chen-Chen made twice as much as David so 36/2=18 So Chen made $9.

David- 36-18= 18 So, David made 18 dollars.

4 0
3 years ago
Awnser me pkeaeeeeeeeeee
postnew [5]

Answer:

46.01

Step-by-step explanation:

i.e sum of all the purchases + 7% of the total purchase.

3 0
3 years ago
5th grade math. Correct answer will be marked brainliest
Verizon [17]

Answer:

17/24

taking L.C.M between 6 and 8

we get 24

therefore,(20-3)/24=17/24

6 0
3 years ago
Read 2 more answers
Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
3 years ago
How many 3/4s are in 3 2/4
MArishka [77]

Answer:

the answer is 3

Step-by-step explanation:

First change the whole number (3) to quaters or fraction

3x \frac{4}{4} = \frac{12}{4}

Now, add

\frac{2}{4} + \frac{12}{4} = \frac{14}{4}   Since, we have the same common denominator

now divide

14÷4 =3.5 = 3\frac{2}{4}

Therefore, there are 3 of 3/4 with a remainder of  \frac{2}{4} in 3 \frac{2}{4}.

7 0
3 years ago
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