1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MakcuM [25]
3 years ago
7

How do u compare rate of change and slope help plz

Mathematics
1 answer:
antoniya [11.8K]3 years ago
4 0

Step-by-step explanation:

The slope is described by the the initial and final value of one quantity over the difference between the initial and final of the other

Rate: for points on a Cartesian plane,(x1, y1) and (x2, y2)

the slope, m= (y2 - y1)/(x2 - x1)

The rate of change on the other hand is mostly refers to how much a quantity is changing with time i.e the rate of change of y from y1 to y2 can be expressed as

rate = (y2 - y1)/(t2 - t1)...where t1 and t2 are the various time in y1 and y2 respectively...

You might be interested in
A tree casts a shadow of 28 m. The elevation of the sun is 49º. How tall is<br> the tree?
Maksim231197 [3]

Answer:

50 M SINCE 50/(length of shadow)=tan49,

Length of shadow=50/tan49=28

I THINK

Step-by-step explanation:

5 0
3 years ago
5. State the missing reasons in this proof.
hammer [34]

Answer:

a.) Vertical Angles

b.) Given (Parallel)

c.) Substitution

Step-by-step explanation:

3 0
3 years ago
A shop sold 14 white shirts, 24 pink shirts, and 28 blue shirts. What is the ratio of the number of pink shirts sold to the numb
natka813 [3]

Answer:

Step-by-step explanation:

24 : 28

Both have table of 4 in common

6 : 7

3 0
3 years ago
4 Student is 20% of ____ students
luda_lava [24]

Answer:

4 Student is 20% of 20 students

Step-by-step explanation:

if 4 = 20% then 1 = 5% to get a hundred percent then you need to multiply by 20

so 20

4 Student is 20% of 20 students

5 0
4 years ago
Read 2 more answers
Which expression represents the sixth term in the binomial expansion of (5y+3)^10
olga nikolaevna [1]
\bf \textit{the coefficient and values of an expanded term}\\\\&#10;(5y-3)^{10} \qquad \qquad &#10;\begin{array}{llll}&#10;expansion\\&#10;for\\&#10;6^{th}~term&#10;\end{array} \quad &#10;\begin{cases}&#10;\stackrel{term}{k}=0..10\\&#10;\stackrel{exponent}{10}\\&#10;-----\\&#10;k=\stackrel{6^{th}~term}{5}\\&#10;n=10&#10;\end{cases}

\bf \stackrel{coefficient}{\left(\frac{n!}{k!(n-k)!}\right)} \qquad \stackrel{\stackrel{first~term}{factor}}{\left( a^{n-k} \right)} \qquad \stackrel{\stackrel{second~term}{factor}}{\left( b^k \right)}

\bf \stackrel{coefficient}{\left(\frac{10!}{5!(10-5)!}\right)} \qquad \stackrel{\stackrel{first~term}{factor}}{\left( (5y)^{10-5} \right)} \qquad \stackrel{\stackrel{second~term}{factor}}{\left( (-3)^5 \right)}&#10;\\\\\\&#10;252(5y)^5(-3)^5\implies 252(5^5y^5)(-3)^5\implies -252(3125y^5)(243)&#10;\\\\\\&#10;-191362500y^5
8 0
3 years ago
Other questions:
  • Alexia made a down payment of $1825 on a car, and then paid 36 monthly payments of $415. If the loan had 0% interest, how much d
    6·1 answer
  • The assumption of homoscedasticity is that _________. the range of the Y scores is the same as the X scores the X and Y distribu
    13·1 answer
  • Justin needs to make 80 illustrates for an art book. He has 40% of the illustrations. Make a bar model to show his progress. How
    6·1 answer
  • If sinA=1/2 what is cosA​
    5·1 answer
  • I need to find the measure
    8·1 answer
  • 1.0 is what percent of 3.5
    10·1 answer
  • The point A (−5,4) is reflected over the point (−2,5) and its image is point B. What are the coordinates of point B?
    9·1 answer
  • When multiplying two terms with tye same base what operation on the exponents​
    11·1 answer
  • A circle is divided up into 24 equal pieces. What percentage of the total circle area will each piece be? Round to the nearest p
    13·2 answers
  • What is the value of x?<br> x = 55°<br> x = 60°<br> x = 70°<br> x = 110°
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!