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Vesna [10]
3 years ago
12

What is 6 more than 7 times a number is 41

Mathematics
1 answer:
son4ous [18]3 years ago
8 0


the problem would be set up as 6+(7*x)=41

first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41

7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9

 so x =5.9

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Question 1
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Answer: Chowder

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3 years ago
PLEASE HELP PLEASE SOLVE ALL!!!
VARVARA [1.3K]

Answer:

x= -6 | I only have an answer for #7 but you should use a website called Symbolab :)

Step-by-step explanation:

x+16+x+12+2x+15=19

<em>group like terms: </em>

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<em>subtract 43 from both sides:</em>

4x+43=19

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<em>simplify</em>:

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<em>divided both sides by 4:</em>

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2 years ago
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Answer:

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Step-by-step explanation:

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