What is 6 more than 7 times a number is 41

Mathematics

1 answer:

son4ous [18]3 years ago

8 0

the problem would be set up as 6+(7*x)=41

first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41

7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9

so x =5.9

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