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3 years ago

Solve the equation by combining like terms. Show all steps. 10w + 4w = -84

Mathematics

2 answers:

Illusion [34]3 years ago

6 0

Answer:

w = -6

Step-by-step explanation:

Like terms would be "terms" with the same variable. 5x and 4x would be like terms, because they have the same variable of x. 6y and 2x would not be like terms, because they have different variables (6y has the variable of y and 2x has the variable of x).

When combining like terms, we would add up the coefficients of the variables and then multiply that by the variable:

4x + 6x = (4 + 6)x = 10x

In other words:

ax + bx = (a + b)x

where x is any variable and a and b are constants.

We are given the equation:

10w + 4w = -84

and we have to solve the equation. To do this, we must first combine the like terms. And than we would try to get the equation into the for "w = _".

10w + 4w = -84

Combine the like terms 10w and 4w.

(10 + 4)w = -84

Simplify.

14w = -84

Divide both sides by 14 to get rid of the coefficient of 14 on the left side.

w = (-84) ÷ 14

Simplify.

w = -6

The solution would be w = -6.

I hope you find my answer helpful. :)

julia-pushkina [17]3 years ago

4 0

Answer:

14w=-84

divide by 14

w= -84/14

w=-6

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3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

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The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

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The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

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At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

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Written in slope-intercept form: y = 1/4x + 6

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