The amount I would receive for the bond when I sell it at the yield to maturity is $810.41.
<h3>How much would I receive for the bond?</h3>
In order to determine the amount I would receive for the bond, the present value of the bond has to be determined. Present value is the discounted cash flow.
Present value = $10000 / (1.0619)^3.5 = $810.41
To learn more about present value, please check: brainly.com/question/26537392
Point-slope form of a line is
y=mx+b
where m is the slope and b is your y intercept
So, if the slope is 5, then that is your m value
y=5x+b
To find the value of b, that is just the value of where the line passes the y axis
Answer:
Step-by-step explanation:
It means that you have to have pi in your answer. For example, if you were finding the area of a circle with a radius of 3, you would do (3)^2*pi and simplify it to just 9pi.
One way is to solve for the invers of the first function
remembe, to solve, replace f(x) or g(x) with y, switch x and y, solve for y and replace it with f⁻¹(x)
A.
f(x)=x/2+8
y=x/2+8
x=y/2+8
x-8=y/2
2x-16=y
f⁻¹(x)=2x-16
nope, not A
B.
f(x)=3x³+16
y=3x³+16
x=3y³+16
x-16=3y³
(x-16)/3=y³
∛((x-16)/3)=y
f⁻¹(x)=∛((x-16)/3)
nope, not the same
not B
C.
f(x)=18/x-9
y=18/x-9
x=18/y-9
x+9=18/y
y(x+9)=18
y=18/(x+9)
f⁻¹(x)=18/(x+9)
correct, the answer is C
answer is C
An inequality that represent the number of cans, c, that Jacob must still collect is 
.
<u>Step-by-step explanation:</u>
Here we have , Jacob needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items. We need to solve the following :
<u>Part A:
</u>
Write and solve an inequality to represent the number of cans, c, that Jacob must still collect.
Jacob has collected 64 cans . Jacob need to collect at least 120 cans for a food drive to earn community service credit , Let Number of cans that Jacob have to collect is c , So following is the inequality for above scenario:
⇒ 
⇒ 
⇒
Therefore , An inequality that represent the number of cans, c, that Jacob must still collect is .
