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3 years ago

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During a manufacturing process, a metal part in a machine is exposed to varying temperature conditions. The manufacturer of the

machine recommends that the temperature of the machine part remain below 141°F. The temperature T in degrees Fahrenheit x minutes after the machine is put into operation is modeled by
T = 0.005x² + 0.45x + 125.
Will the temperature of the part ever reach or exceed 141F? Use the discriminant of a quadratic equation to decide.
A. yes
B. no

1 answer:

mars1129 [50]3 years ago

6 0

Answer:

Yes, it will reach or exceed 141 degree F

Step-by-step explanation:

Given equation that shows the temperature T in degrees Fahrenheit x minutes after the machine is put into operation is,

$T = 0.005x^2 + 0.45x + 125$

Suppose T = 141°F,

$\implies 141 = 0.005x^2 + 0.45x + 125$

$\implies 0.005x^2 + 0.45x + 125 - 141 =0$

$\implies 0.005x^2 + 0.45x - 16=0$

Since, a quadratic equation $ax^2 + bx + c =0$ has,

Real roots,

If Discriminant, $D = b^2 - 4ac \geq 0$

Imaginary roots,

If D < 0,

Since, $0.45^2 - 4\times 0.005\times -16 = 0.2025 + 32 > 0$

Thus, roots of -0.005x² + 0.45x + 125 are real.

Hence, the temperature can reach or exceed 141 degree F.

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Read 2 more answers

PLEASE HELP !!!!!!! Jordan got a new money bank for his birthday with $20 inside. He puts part of his weekly allowance in his ba

kupik [55]

Answer:

Slope of the function is $=3.75$ ,Y-intercept $=20$ .

The function is $y=3.75(x)+20$ with initial value $=20$ ,Jordan puts $\$3.75$ each week andthe amount saved by Jordan after $52$ week $=215\$$ .

Step-by-step explanation:

To understand the slope and y-intercept lets assign $x$ as number of weeks and $y$ as the money saved by Jordan.

Jordan is already having a sum of $\$20$ inside the money bank so in $0$ week the amount is $\$20$ can be written as $(x,y) =(0,20)$ in coordinate form.

SImilarly

We have $(x,y) =(0,20)$ and $(x_1,y_1) =(25,113.75)$

Part A:

The function is $y=m(x)+b$

From point-slope form,we have slope (m)

and $m=\frac{y_1-y}{x_1-x}$ ,plugging the values of the points.

$m=\frac{113.75-20}{25-0}=3.75$

Y-intercept of this function is the constant term or the money of $\$20$ that is already inside the money bank.

We can also calculate y-intercept by arranging the function as $b=y-m(x)$ choosing any $(x_1,y_1) = (25,113.75)$ coordinate and here $b$ is the y-intercept.

The result will be same.

Part B:

The equation <u> $y=3.75(x)$ </u> can represent the function described.

And the initial value is the <u>y-intercept $=\$20$ </u>

Jordan puts<u> $3.75$ </u>in his bank each week.

After $52$ week the amount saved by Jordan ,here $x=52$ ,as the x-variable is the number of weeks.

Plugging the value of $x=52$ in $y=m(x)+b$ where $m=3.75$ so the equation becomes $y=3.75(x)+20$

$y=3.75(x)+20 =3.75(52)+20=\$215$

So basically the function is $y=3.75(x)+20$ and the amount saved by Jordan after $52$ week $=215\$$ .

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3 years ago