All categories

3 years ago

-12=-2(2-8) Is it true false or an open sentence

2 answers:

7 0

The statement is false because when you use distributive property, you get -12=-4+16 and when you add 16 to -4, you'll get 12, not -12, making the statement false.

pochemuha3 years ago

5 0

False because -12 does not equal -6

You might be interested in

What are the measures of Angles a, b, and c? Show your work and explain your answers.

labwork [276]

∠a is 35° because of vertical angle congruence. ∠b is 55° because one angle is right, so the other two have to add up to 90°, and 90°-35°=55°. ∠c is 110° because it creates a straight angle (180°) with the 70° angle, and 180°-70°=110°.

7 0

3 years ago

Noah has just graduated high school and has some credit card offers! The first credit card (Credit Card A) charges 18% compounde

Usimov [2.4K]

Answer:

it would be 39

Step-by-step explanation:

3 0

3 years ago

I need to know the answers

kkurt [141]

Answer:

for which problems if it is all the ones you haven't done yet then say that.

Step-by-step explanation:

i dont know how to gragh pionts on this thing plz tell me how

7 0

3 years ago

Read 2 more answers

Rewrite the following integral in spherical coordinates.

lora16 [44]

In cylindrical coordinates, we have $r^2=x^2+y^2$ , so that

$z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}$

correspond to the upper and lower halves of a sphere with radius $\sqrt2$ . In spherical coordinates, this sphere is $\rho=\sqrt2$ .

$1 \le r \le \sqrt2$ means our region is between two cylinders with radius 1 and $\sqrt2$ . In spherical coordinates, the inner cylinder has equation

$x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)$

This cylinder meets the sphere when

$x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)$

which occurs at

$\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi$

where $n\in\Bbb Z$ . Then $\frac\pi4\le\phi\le\frac{3\pi}4$ .

The volume element transforms to

$dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi$

Putting everything together, we have

$\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3$

4 0

2 years ago

Find the measure of the angle.

Finger [1]

Answer:

the awnser should be. 165

5 0

3 years ago

Read 2 more answers