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777dan777 [17]
3 years ago
15

Help me please!!!!!!!!!!!!!

Mathematics
1 answer:
QveST [7]3 years ago
7 0

Step-by-step explanation:

0 < X < 24

.....................

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(3x-8)° (4x-23)° fine the x
Veronika [31]

You cannot find x.

Because both phrases are to the power of 0, we know that it is essentially 1*1

So:

(3x - 8)^0 (4x - 23)^0 = 1

7 0
3 years ago
I NEED HELP WITH A),B),and C) ASAP!!! Please helpp:/
Dennis_Churaev [7]
A=positive because if he get some of the negatives then the number will either turn 0 or negative and has to go inthe pile

b=-0.3or-0.4or-0.5
-0.2-0.3=0.1
-0.2-0.4=0.2
-0.2-0.5=0.3

c=-0.1or-0.2
-0.2-0.1=-0.1
-0.2-0.2=0
one is negative and the other is 0 so they must go back in the pile
3 0
3 years ago
ASAP wats the answer!?!?!
Vesnalui [34]
1. Corresponding
2. No not supplementary
3. 132
4 0
3 years ago
Rahul, a coach at a local school has collected data on his players. But in an accident he lost how many games each player partic
Arada [10]

Answer:

Michael played 4 games, Sherry played 6 games and Rashad played 5 games

Step-by-step explanation:

Let X, Y and Z represents the  number of games for the three players.

Based on the given information, three equations can be formed -

30 X + 25 Y + 20 Z = 370 ---(1)

X + Y + 2Z = 20 ---(2)

2X + 5Y + 4 Z = 58 ---(3)

From Equation (2), X = 20 -Y-2Z

Substituting value of X from equation 2, in equation 1 and 2, we get -

30 (20-Y-2Z) + 25 Y + 20 Z = 370

600 -30Y-60Z + 25 Y + 20 Z = 370

-5Y -40Z = -230

Y + 8Z = 46 ----(4)

2(20-Y-2Z) + 5Y + 4 Z = 58

40 -2Y-4Z + 5Y + 4 Z = 58

3Y = 18

Y = 6

Substituting value of Y in equation 4, we get -

8Z = 46-6

8Z = 40

Z = 5

Substituting value of Y and Z in equation 2 we get

X + 6 + 2* 5 = 20

X = 20-16 = 4

Hence, Michael played 4 games, Sherry played 6 games and Rashad played 5 games

5 0
3 years ago
The question is in the picture.
dangina [55]
<h2><u>Part A:</u></h2>

Let's denote no of seats in first row with r1 , second row with r2.....and so on.

r1=5

Since next row will have 10 additional row each time when we move to next row,

So,

r2=5+10=15

r3=15+10=25

<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>

r1=5=5+0=5+0×10=5+(1-1)×10

r2=15=5+10=5+(2-1)×10

r3=25=5+20=5+(3-1)×10

<u>So for nth row,</u>

rn=5+(n-1)×10

Since 5=r1 and 10=common difference (d)

rn=r1+(n-1)d

Since 'a' is a convention term for 1st term,

<h3><u>⇒</u><u>rn=a+(n-1)d</u></h3>

which is an explicit formula to find no of seats in any given row.

<h2><u>Part B:</u></h2>

Using above explicit formula, we can calculate no of seats in 7th row,

r7=5+(7-1)×10

r7=5+(7-1)×10 =5+6×10

r7=5+(7-1)×10 =5+6×10 =65

which is the no of seats in 7th row.

8 0
4 years ago
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