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2 years ago

Which line is parallel to a line that has a slope of 3 and a y-intercept at (0, 0)?

Mathematics

1 answer:

saul85 [17]2 years ago

4 0

Answer:

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are the same

The slope of the line that is parallel to a line that has a slope of 3 is equal to 3

Verify the slope of the blue and red line , because their slopes are positive

Blue line

we have

C(-3,0),D(3,2)

The slope m is equal to

m=(2-0)/(3+3)

m=2/6

m=1/3

Red line

we have

H(-1,-4),J(1,2)

The slope m is equal to

m=(2+4)/(1+1)

m=6/2

m=3

therefore

The answer is the red line HJ

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Evaluate each geometric series described 3 + 6 +12 + 24 n=7

baherus [9]

Process:

1. 21+24n= 7
2. 24n= 7 - 21
3. 24n= -14

Answ: n= -7/12

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2 years ago

For z = 2cispi/6, find z^5 in reactangular form.

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2 years ago

A man invests his savings in two accounts ,one paying6% and the other paying 10% simple interest per year. He puts twice as much

AnnyKZ [126]

Answer: he invested $46062.5 at 6% and $23031.25 at 10%

Step-by-step explanation:

Let x represent the amount which he invested in the account paying 6% interest.

Let y represent the amount which he invested in the account paying 10% interest.

He puts twice as much in the lower-yielding account because it is less risky.. This means that

x = 2y

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account paying 6% interest,

P = $x

T = 1 year

R = 6℅

I = (x × 6 × 1)/100 = 0.06x

Considering the account paying 10% interest,

P = $y

T = 1 year

R = 10℅

I = (y × 10 × 1)/100 = 0.1y

His annual interest is $7370dollars. it means that

0.06x + 0.2y = 7370 - - - - - - - - - -1

Substituting x = 2y into equation 1, it becomes

0.06 × 2y + 0.2y = 7370

0.12y + 0.2y = 7370

0.32y = 7370

y = 7370/0.32

y = $23031.25

x = 2 × 23031.25

x = 46062.5

6 0

2 years ago

2. Which of the following proves that 209 is NOT a prime number?

solmaris [256]

the answer is B) 19 × 11 = 209

coz A prime number is a whole number greater than 1 whose only factors are 1 and itself.

but here it is a multiple of 11 and 19 ....

so its proved

5 0

3 years ago

what is te discontinuity of the function f(x) = the quantity of x squared plus 6x plus 8 all over x plus 4?

seropon [69]

Answer:

A hole at x=-4.

Step-by-step explanation:

This is a fraction so we have to worry about division by zero.

The only time we will be dividing by 0 is when x+4 is 0.

Solving the equation

x+4=0 for x:

Subtract 4 on both sides:

x=-4

So there is either a vertical asymptote or a hole at x=-4.

These are the kinds of discontinuities we can have for a rational function.

If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.

If is is a vertical asymptote, x=-4 will make the top NOT zero.

Let's see what -4 for x in x^2+6x+8 gives us:

(-4)^2+6(-4)+8

16+-24+8

-8+8

Top and bottom are 0 when x=-4.

Let's see what happens after simplication.

We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.

So what 2 numbers together multiply to be 8 and add up to be 6.

I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.

$\frac{x^2+6x+8}{x+4}=\frac{(x+4)(x+2)}{x+4}=x+2$

We we able to cancel out that factor that was giving us x=-4 is a zero.

Therefore there is a hole at x=-4.

7 0

3 years ago