Answer: The height of the flagpole is 12 feet.
Step-by-step explanation:
Let the height of the flagpole be 'H'.
So, from the figure, we can conclude that, the height and shadow of the flagpole is in proportion to the height and shadow of the stick.
Given:
Height of stick is,
Shadow of the stick is,
Shadow of the flagpole is,
Now, as these are in proportion, we have
Plug in the given values and solve for 'H'. This gives,
Hence, the height of the flagpole is 12 feet.
Answer:
∠EFG = 48°
Step-by-step explanation:
As FH bisects ∠EFG , ∠EFH = ∠HFG .
We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°
Also, ∠HFG + ∠EFH = ∠EFG
=> 2(-5x + 89)° = (61 - x)°
=> -10x + 178 = 61 - x
=> 10x - x = 178 - 61
=> 9x = 117
=> x = 117 / 9 = 13
Putting the value of 'x' in ∠EFG gives :-
(61 - x)° = (61 - 13)° = 48°
4 for 16 would be written as 4/16.
Dividing both numbers by 4 it is simplified to 1/4
