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3 years ago

How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?

2 answers:

8 0

The answer is one (A)
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storchak [24]3 years ago

7 0

A.) One

[ That Triangle must be Scalene with three different sides ]

Hope this helps!

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Help me like please just help me and don’t answer if u don’t know the answer

Mila [183]

I think it is .8 i could be wrong i’m not sure

7 0

3 years ago

Read 2 more answers

Round 18.049 to the nearest tenth.

kirill115 [55]

Answer:

18.0

Step-by-step explanation:

Note the tenth place value (underlined and bolded): 18.<u>0</u>49

Look at the number to the direct right of the tenth place value (or the hundredth place value in this case). It is a 4.

Note the rules of rounding. If the number:

1) is 5 or greater, round up.

2) is 4 or less, round down.

In this case, it is 4, so you will round down.

18.049 rounded to the nearest tenth is 18.0

4 0

3 years ago

Read 2 more answers

In a circle of radius 10 cm, a sector has an area of 40 (pi) sq. cm. What is the degree measure of the arc of the sector?

Rashid [163]

Answer:

144°

Step-by-step explanation:

First, find the area of the circle, with the formula A = $\pi$ r²

Plug in 10 as the radius, and solve

A = $\pi$ r²

A = $\pi$ (10²)

A = 100 $\pi$

Using this, create a proportion that relates the area of the sector to the degree measure of the arc.

Let x represent the degree measure of the arc of the sector:

$\frac{40\pi }{100\pi }$ = $\frac{x}{360}$

Cross multiply and solve for x:

100 $\pi$ x = 14400 $\pi$

x = 144

So, the degree measure of the sector arc is 144°

6 0

3 years ago

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99PTS!!!!!!!

Ostrovityanka [42]

h(x) = 3^x – 2 will be negative when x is less than 0

h(2) =7

g(2)=7

This is the point they are equal

g(x)> h(x) until2

g(x)>=h(x) -2<=x<=2

Choice A

5 0

3 years ago

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Which expressions are algebraically equivalent to the correct usage of the distance formula to find the distance from point A(3,

egoroff_w [7]

Answer:

(5)

Step-by-step explanation:

The given two points are:

A(3,k) and B(h,4)

Now, using the distance formula that is= $\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}$ .

In the given points, $y_{2}=4$ , $y_{1}=k$ , $x_{2}=h$ and $x_{1}=3$ , thus,

$\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}$ = $\sqrt{(4-k)^{2}+(h-3)^{2}}$

which is the required equation, hence option 5 is correct.

8 0

3 years ago

Read 2 more answers