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Schach [20]
3 years ago
9

A doughnut shop sells 30 kinds of doughnuts. in how many ways can you (a) get a bag of 12 doughnuts?

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer:

there are 86493225 possible ways you can get a bag of 12 doughnuts

Step-by-step explanation:

since we do not care about the order of the donuts in the bag ,we will need to calculate the number of possible combinations for 30 different elements in a group of 12 , then:

Number of combinations=C= n! /[(n-r)!*r!]

where n= number of elements , r= group size

replacing values

C= n! /[(n-r)!*r!] = 30!/[(30-12)!*12!] = 86493225 possible combinations

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The first thing we do is raise the last monomial to the third power.

(4xy)(2x</span>²<span>y)(3xy)</span>³
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Now we can multiply the first two monomials. When we multiply powers with the same base, we add the exponents:
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We multiply these last two monomials, again adding the exponents:
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\\ \sf\longmapsto tan\Theta=\dfrac{P}{B}

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