I need help asap I don't get this

A rectangular area is to be fenced in with 300 feet of chicken wire. find the maximum area that can be enclosed.

GarryVolchara [31]

Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.

2(x+y) = 300
x+y = 150
y = 150-x

A=x(150-x) <--(substitution)

The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150

So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.

A=75(150-75)
A=75*75
A=5625

So the maximum area that can be enclosed is 5625 square feet.

6 0

3 years ago

Two life insurance policies, each with a death benefit of 10,000 and a one-time premium of 500, are sold to a couple, one for ea

Kazeer [188]

Answer:896.9

Step-by-step explanation:

Let x denotes excess premium over claims

$E\left ( x|husband survives\right )$ , There are two possibilities

(i)Only husband survives

This can be possible with a possibility of 0.01

Claims=10,000

Premium collected $=2\times 500=1000$

Thus x=1000-10,000=-9000

(ii)Both husband and wife survives

This can occur with a probability of 0.96

Here claims will be 0 as both survives

Premium taken=1000

thus x=1000

The probability that the husband survives is the sum of above cases

=0.96+0.01=0.97

Hence the desired conditional Expectation $E\left ( x|Husband survives\right ) =0.01\times \left ( -9000\right )+0.96\times \left ( 1000\right )=896.9$

7 0

3 years ago

A rectangle has an area of 171 square meters. Its width is ten meters less than the length. Find the measures of the length and

9966 [12]

Step-by-step explanation:

The area of a rectangle is 171 m²

Let l is the length and b is the width of the rectangle

It width is 10 m less than the length. So,

b = l-10 ...(1)

Area of a rectangle is given by :

$A=l\times b\\\\171=l(l-10)\\\\l^2-10l=171\\\\l^2-10l-171=0\\\\l^2-19l+9l-171=0\\\\\text{taking common together}\\\\l(l-19)+9(l-19)=0\\\\(l-9)(l-19)=0$

or

l = 9 m or l = 19 m

If l = 9 m,

b = 9-10 = -1 m (can't be possible)

If l = 19 m

b = 19-10 = 9 m

So, the length an the breadth of the rectangle is 19 m and 9 m respectively.

8 0

2 years ago

Identify each line or segment that intersects ⊙ S.

Delicious77 [7]

Answer:

AC, CE, AB, and AS

I belive those are your answers

7 0

2 years ago

Read 2 more answers

Item 18 you and your friend are selling tickets to a charity event. you sell 7 adult tickets and 16 student tickets for $120. yo

quester [9]

Answer:

$4

Step-by-step explanation:

The two purchases can be written in terms of the cost of an adult ticket (a) and the cost of a student ticket (s):

7a +16s = 120 . . . . . . . . price for the first purchase

13a +9s = 140 . . . . . . . . price for the second purchase

Using Cramer's rule, the value of s can be found as ...

s = (120·13 -140·7)/(16·13 -9·7) = 580/145 = 4

The cost of a student ticket is $4.

_____

<em>Comment on Cramer's Rule</em>

Cramer's rule is particularly useful for systems that don't have "nice" numbers that would make substitution or elimination easy methods to use. If you locate the numbers in the equation, you can see the X-patterns that are used to compute the numerator and denominator differences.

The value of a is (16·140 -9·120)/(same denominator) = 1160/145 = 8. I wanted to show you these numbers so you could see the numerator X-pattern for the first variable.

__

Of course, graphical methods can be quick and easy, too.

8 0

3 years ago