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3 years ago

5

Determine which ordered pairs are part of the solutions set for the inequality.(Hint - There may be more than 1 correct answer)"

1 answer:

Alisiya [41]3 years ago

6 0

These ordered pairs<span> are in the </span>solution set<span> of the equation </span>x<span> > </span>y. ... (2<span>, </span>0<span>). </span>3(2<span>) + </span>2(0<span>) ≤ 6. 6 + </span>0<span> ≤ 6. 6 ≤ 6. (</span>4, −1<span>). </span>3(4<span>) + </span>2(−1) ≤ 6. 12 + (−2<span>) ≤ 6 ... </span>3<span>). </span>

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Ronch [10]

Answer:

<em><u>1 and 5</u></em>

Step-by-step explanation:

The squares have a side length of 10 and 1 square side is the radius of the half-circles. Since there are two half-circles, find the circumference for one full circle:

$C=2\pi r$

Insert the radius:

$r=10\\C=2\pi *10$

Simplify pi:

$C=2*3.14*10$

Simplify multiplication:

$C=6.28*10\\C=62.8$

The circumference of the circles is 62.8. Now find the perimeter of the exposed squares with side length 10. There are 4 exposed sides, which equals one square. Find the perimeter:

$P=10+10+10+10\\P=10+10+20\\P=10+30\\P=40$

Add the perimeter of the circle and the square together:

$P=62.8+40=102.8$

Now see which of the options gives you the perimeter:

1. $40+20\pi =102.8$ ****

2. $unavailable$

3. $120+20\pi =182.8$

4. $300+100\pi =614.2$

5. $10+10+10\pi +10+10+10\pi =102.8$ ****

Finito.

7 0

2 years ago

A car travels at an average speed of

zheka24 [161]

I think it is 264 divided by 48 = 5.5 (5 and a half hours)

May want to check but I think this is correct

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3 years ago

xand y are light house. y being 20km due east of x and from a ship due south of x the bearing of y was 055°. what is the distanc

leonid [27]

Answer:

I) |xz| ≈ 28.6 km

II) |yz| ≈ 34.8 km

Step-by-step explanation:

Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)

|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°

Using Trigonometric ratio - SOHCAHTOA

I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20

|xz| = 20 * Tan 55 = 20 * 1.428

|xz| = 28.56 km

|xz| ≈ <u>28.6 km</u>

<u />

II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|

|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°

|yz| = 20 ÷ 0.574 = 34.84 km

|yz| ≈ <u>34.8 km</u>

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3 years ago

Count by five from 135 to 175.write these numbers and describe the pattern

guapka [62]

135, 140, 145, 150, 155, 160, 165, 170, 175. The last digit is either a 0 or a 5. I hope this helped. :) Brainlest answer?

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Identify the property shown .<br><br> 50+0=50

qwelly [4]

The identity property is shown

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3 years ago