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blondinia [14]
4 years ago
5

Determine which ordered pairs are part of the solutions set for the inequality.(Hint - There may be more than 1 correct answer)"

Mathematics
1 answer:
Alisiya [41]4 years ago
6 0
These ordered pairs<span> are in the </span>solution set<span> of the equation </span>x<span> > </span>y. ... (2<span>, </span>0<span>). </span>3(2<span>) + </span>2(0<span>) ≤ 6. 6 + </span>0<span> ≤ 6. 6 ≤ 6. (</span>4, −1<span>). </span>3(4<span>) + </span>2(−1) ≤ 6. 12 + (−2<span>) ≤ 6 ... </span>3<span>). </span>
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Write an equation in point slope form for the given line
PtichkaEL [24]

Answer:

\large\boxed{y-4=-\dfrac{1}{2}(x-1)}

Step-by-step explanation:

Look at the picture.

The formula of a slope:

The point-slope form of an equation of a linear function:

y-y_1=m(x-x_1)

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (1, 4) and (-3, 6). Substitute:

m=\dfrac{6-4}{-3-1}=\dfrac{2}{-4}=-\dfrac{1}{2}\\\\y-4=-\dfrac{1}{2}(x-1)

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3 years ago
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g100num [7]

Answer:

x≤3 or x>10

Step-by-step explanation:

x≤3 because the dot is a solid dot at 3 and pointing backward toward numbers less than 3.

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6 0
3 years ago
Airen’s grandparents deposited $1300 in a mutual fund earning 6% interest compounded annually. Write an equation to represent ho
IRINA_888 [86]

~~~~~~ \textit{Compound Interest Earned Amount \underline{in 18 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1300\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &18 \end{cases}

A=1300\left(1+\frac{0.06}{1}\right)^{1\cdot 18}\implies A=1300(1.06)^{18}\implies A\approx 3710.64 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y = 1300(1.06)^x~\hfill

7 0
3 years ago
Solve <br> (3x+4) (2x-1)=0 <br> X(4x+3)= 0
kotegsom [21]

Answer:

x = -4/3     x = 1/2

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Step-by-step explanation:

(3x+4) (2x-1)=0

Using the zero product property

3x+4 = 0   2x-1 =0

3x= -4     2x= 1

x = -4/3     x = 1/2

x (4x+3) =0

Using the zero product property

x = 0   4x+3 = 0

x=0  4x=-3

x=0   x = -3/4

5 0
4 years ago
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