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blondinia [14]
3 years ago
5

Determine which ordered pairs are part of the solutions set for the inequality.(Hint - There may be more than 1 correct answer)"

Mathematics
1 answer:
Alisiya [41]3 years ago
6 0
These ordered pairs<span> are in the </span>solution set<span> of the equation </span>x<span> > </span>y. ... (2<span>, </span>0<span>). </span>3(2<span>) + </span>2(0<span>) ≤ 6. 6 + </span>0<span> ≤ 6. 6 ≤ 6. (</span>4, −1<span>). </span>3(4<span>) + </span>2(−1) ≤ 6. 12 + (−2<span>) ≤ 6 ... </span>3<span>). </span>
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never [62]
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Four ways on how save water​
irina1246 [14]
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3 years ago
A ball was drawn from a bag containing 10 red, 30 white, 20 blue, and 15 yellow balls. what is the probability that it is neithe
Wittaler [7]
There are a total of 75 balls in the bag.

45 of these balls are neither red nor blue.

45/75 = .60

There is a 60% chance that a ball that in not red or blue will be chosen.

Hope this helps!
7 0
3 years ago
Describe a scenario where the function value exists at x=c, but the limit does not exist.
Vikki [24]

The scenario can be described using a piecewise function like:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

<h3>When the value exists but the limit does not?</h3>

Remember that the limit only exists if the limit from left and the limit from the right give the same value.

Then, we can just define a piecewise function of the form:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

Clearly, this is not a continuous function.

Notice that:

f(c) = c.\\\\ \lim_{x \to c^{-}} f(x) = 1/c\\\\ \lim_{x \to c^{+}} f(x) = 1/(c + 73)

So the limits from left and right are different, then:

\lim_{x \to c^{}} f(x)

Does not exist.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0
2 years ago
There are 12 football teams in a competition. The lions have a probability of 1/12 of winning the competition. How is this true?
MaRussiya [10]
Asuming that all the teams have the same skill levels the game will mostly be chance. The chance of winning will be 1/12 because they are 1 out of 12 teams.
7 0
3 years ago
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