The extraneous solution of the given radical equation is x = 3
<h3>
Finding the extraneous solution:</h3>
Here we have the radical equation:

We want to get the extraneous solution, to get it, we first need to square both sides of the equation, so we get:

Now we got a quadratic equation, we can rewrite it as:

To solve this we use Bhaskara's formula, we will get:

Then the two solutions are:
x = (15 + 9)/2 = 12
x = (15 - 9)/2 = 3
<h3>Which one is the extraneous solution?</h3>
Let's evaluate both solutions in our original equation and let's see which is the one that does not work:
for x = 12 we have:

This is true.
For x = 3 we have:

This is false, so the extraneous solution is x = 3.
If you want to learn more about extraneous solutions, you can read:
brainly.com/question/2959656
Answer:
8(5x+3)
Step-by-step explanation:
Answer:
A (2,-1)
Step-by-step explanation:
-1 = 3(2) -7
5(2) - (-1) = 11
x - 2/3 = 5/6
the only step needed is to add 2/3 to 5/6
2/3 + 5/6 = 1 1/2
x = 1 1/2
Answer:
y = -2x+2
Writing the slope was the more difficult part. Writing the y-intercept was the easiest because I had to select to points on the line and solve to get the slope. The y-intercept was already explicitly shown on the line.
Step-by-step explanation:
y = mx+b
y = -2x + 2