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konstantin123 [22]
3 years ago
7

How do i Solve: 3x2−6x−12=0 ?

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

1 + root 5, 1 - root 5

Step-by-step explanation:

I assume you mean 3x^2-6x-12=0.

First, note that you can divide both sides by 3. You get:

x^2-2x-4=0

Use the quadratic equation.

x=\frac{2\pm\sqrt{4+16}}{2}=\frac{2\pm2\sqrt{5}}{2}=1\pm\sqrt{5}

Therefore, x=1 + root 5, 1 - root 5

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Step-by-step explanation:

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Pythagorean Theorem:

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