Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
The first thing we are going to do is to fill in the other angles that we need to solve this problem. You could find ALL of them but all of them isn't necessary. So looking at the obtuse angle next to the 35 degree angle...we know that those are supplementary so 180 - 35 = the obtuse angle in the small triangle. 180 - 35 = 145. Within the smaller triangle we have now the 145 and the 10, and since, by the Triangle Angle-Sum Theorem all the angles have to add up to equal 180, then 180 - (10 + 145) = the 3rd angle, so the third angle is 180 - 155 = 25. Now let's get to the problem. If I were you, I'd draw that out like I did to keep track of these angles cuz I'm going to name them by their degree. In order to find d, we need to first find the distance between d and the right angle. We'll call that x. The reference angle is 35, the side opposite that angle is 12 and the side we are looking for, x, is adjacent to that angle. So we will use the tan ratio to find x:
Isolating x:
so
x = 17.1377 m
Now we have everything we need to find d. We will use 25 degrees as our reference angle, and the side opposite it is 12 and the side adjacent to it is
d + 17.1377, so that is the tan ratio as well:
and simplifying a bit:
and a bit more:
d + 17.1377 = 25.73408 so
d = 8.59, rounded
Answer:
The discrete data can be number of legs, number of teeth.
The continuous data can be the length of tail, and the height of dog.
Step-by-step explanation:
Consider the provided information.
The discrete data is a data whose value is obtained by counting and they can be described by an integer value.
So, the discrete data can be number of legs, number of teeth.
A continuous data is a variable whose value is obtained by measuring.
The continuous data can be the length of tail, and the height of dog.
The given plane has normal vector

Scaling <em>n</em> by a real number <em>t</em> gives a set of vectors that span an entire line through the origin. Translating this line by adding the vector <2, 1, 1> makes it so that this line passes through the point (2, 1, 1). So this line has equation

This line passes through (2, 1, 1) when <em>t</em> = 0, and the line intersects with the plane when

which corresponds the point (3, -1, 1) (simply plug <em>t</em> = 1 into the coordinates of
).
So the distance between the plane and the point is the distance between the points (2, 1, 1) and (3, -1, 1):
