Solve 2x>7 } pls help

Sam rented a bike one day in the summer. He paid $68 an hour and a rental fee of $85.00 If Sam paid $ 357.00 for the day, how ma

Sliva [168]

Answer:

4

Step-by-step explanation:

First of all, subtract the rental fee. 357 - 85 = 272. Now, simply divide 272 by 68 to find the number of hours. 272 / 68 = 4.

3 0

2 years ago

Read 2 more answers

1. 2X + 1 = Y<br> 2Y = 6<br> Show your work

slamgirl [31]

Answer:

x = 1

y = 3

Step-by-step explanation:

2x + 1 = y ------- eqn (1)

2y = 6--------eqn (2)

from eqn(2)

2y = 6

y = 3

when you divide 6 by 2y

substitute y = 3 into eqn (1)

2x + 1 = y

2x + 1 = 3

2x = 3-1

2x = 2

therefore

x = 1

4 0

3 years ago

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$

At t = 0

$C(0) = 8(e^{(0)}-e^{(0)}) = 0$

At t = 2

$C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185$

At t = 12

$C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059$

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

4 0

3 years ago

What is the solution to the equation below?Round your answer to two decimal places.3*In x=9.9

storchak [24]

See photo for solution

8 0

3 years ago

anonymous 2 years ago If you were to solve the following system by substitution, what would be the best variable to solve for an

Ainat [17]

I'm sorry that I'm not in calculus, but hopefully I can help.
Personally, I would choose: D.) x; in the second equation ;
because it has easier numbers to figure out, you'll get it eventually...

7 0

3 years ago