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adelina 88 [10]
3 years ago
6

I need help ~again~ o.O

Mathematics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

A= (2,4)

B= Infinitly Many Solutions

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=5%20-%205%20%5Ctimes%202%20%2B%2011" id="TexFormula1" title="5 - 5 \times 2 + 11" alt="5 - 5 \
Rasek [7]

Answer:

6

Step-by-step explanation:

We use BODMAS/BIDMAS here.

First, we do 5 × 2, as multiplication comes before subtracting and adding.

5 × 2 = 10

Now we can just add and subtract.

5 - 10 = -5

-5 + 11 = 6

3 0
3 years ago
What is [(6.2x8.4) minus 9.28]
igor_vitrenko [27]
The answer is 42.8

I hope that helps<span />
8 0
3 years ago
Read 2 more answers
Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number
Gnoma [55]

Sum/difference:

Let

x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}

This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

x = -15\sqrt{8}

if again we assume x to be rational, we have

\sqrt{8} = -\dfrac{x}{15}

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0
3 years ago
MATH HELP PLEASE. ( 40 PTS )
Daniel [21]
The circumference is 75.4 :)
8 0
4 years ago
Read 2 more answers
Can anyone explain how this problem is done ?
Svetach [21]

B

Step-by-step explanation:

6 0
3 years ago
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