The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
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Answer:
<em>C. y = 3x + 13.</em>
Step-by-step explanation:
The point slope form of a line is
y - y1 = m(x - x1) where m = the slope, and (x1, y1) is a point on the line.
So, substituting:
y - 1 = 3(x - -4)
y - 1 = 3(x + 4)
y = 3x + 12 + 1
y = 3x + 13.
The answer will be 250 because you divide 2 by 500
Heyy it’s 1:50! you would put the original two numbers in a ratio 16:800 divide by 8 and get 2:100 then divide by 2 and get 1:50!
