(2/3)=0.66667=x/y
x+y=60
x=60-y
(60/y)-1=2/3
60/y=5/3
y=36
x+36=60
x=24
24:36
The answer to ur problem is 1/3.
45 because if he had any less, there would be left overs for either the 5 per page or 9 per page.
Angle EJM (69°) and Angle KJL(69°) will EACH equal one half of the intercepted arcs.
So, 69° = .5 * (arc EM + arc KL)
69° = .5 * (58° + arc KL)
69° = 29 + .5 *arc KL
40° = .5 * arc KL
Therefore arc KL = 80°
Source:
http://www.1728.org/circangl.htm
answer is B
Answer is D. last one.
hope it helps
