There will have to be 5 because of the 4
A nine can go into a 20 two whole times. After that, there's still
some room left in the 20, but it's only enough room for a 2.
Answer: 
<u>Step-by-step explanation:</u>

Restriction: 6x + 3 ≠ 0 <em>denominator cannot be zero</em>
<u> -3 </u> <u> -3 </u>
6x ≠ -3
<u> ÷6 </u> <u>÷6 </u>
x ≠ 
Answer:
7x + 7
Step-by-step explanation:
2x + 5x = 7x
5 +2 = 7
The answer to this question:
h=-12