Answer:
37
-114
18
-8
Step-by-step explanation:
Just perform the operations eg 46 - 9 = 37.
Step-by-step explanation:
I know your ur mom killed ur dad.
Answer:
a) The cumulative distribution function would be given by:
x 0 1 2 3 4 5
F(X) 0.05 0.15 0.30 0.55 0.9 1
b) ![P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85](https://tex.z-dn.net/?f=%20P%281%20%5Cleq%20X%20%5Cleq%204%29%20%3D%20F%284%29%20-F%280%29%20%3D0.9-0.05%20%3D%200.85%20)
And replacing we got:
![P(1 \leq X \leq 4) =0.85](https://tex.z-dn.net/?f=P%281%20%5Cleq%20X%20%5Cleq%204%29%20%3D0.85)
Step-by-step explanation:
For this case we have the following probability distribution function given:
x 0 1 2 3 4 5
P(X) 0.05 0.1 0.15 0.25 0.35 0.1
We satisfy the conditions in order to have a probability distribution:
1) ![\sum_{i=1}^n P(X_i)=1](https://tex.z-dn.net/?f=%20%5Csum_%7Bi%3D1%7D%5En%20P%28X_i%29%3D1)
2) ![P(X_i) \geq 0, i=1,2,..,n](https://tex.z-dn.net/?f=%20P%28X_i%29%20%5Cgeq%200%2C%20i%3D1%2C2%2C..%2Cn)
Part a
The cumulative distribution function would be given by:
x 0 1 2 3 4 5
F(X) 0.05 0.15 0.30 0.55 0.9 1
Part b
For this case we want to find this probability:
![P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85](https://tex.z-dn.net/?f=%20P%281%20%5Cleq%20X%20%5Cleq%204%29%20%3D%20F%284%29%20-F%280%29%20%3D0.9-0.05%20%3D%200.85%20)
And replacing we got:
![P(1 \leq X \leq 4) =0.85](https://tex.z-dn.net/?f=P%281%20%5Cleq%20X%20%5Cleq%204%29%20%3D0.85)
Felices 6000 pues hay muchos osos