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Marat540 [252]
3 years ago
13

Problems 7and 8 50 POINTS

Mathematics
2 answers:
frez [133]3 years ago
4 0

Answer:

To find the area of a rectangle, you do Length times width. 11 times 8 equals 88, so the width would have to be 8. To find the perimeter, you add up all of the sides. If the width is 8, and the perimeter is 46, 8+8=16 and 48-16 = 30 then the length is 15.

Vinil7 [7]3 years ago
3 0
Try to add "ft" or "in" next to your answer, making "8 ft" rather than 8. Otherwise, your answer is correct.
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The figure is made up of a cylinder and a sphere which has been cut in half. The radius of each half sphere is 5 mm. What is
alexgriva [62]
<h2>Answer:</h2>

<em>Rounded to the nearest hundredth the volume of the composite figure is:</em>

<em>1308 33 cubic millimeters</em>

<h2>Explanation:</h2>

Hello! I wrote the complete question in a comment above. The volume of a cylinder is defined as:

V_{c}=\pi r^2 h \\ \\ r:radius \\ \\ h:height

While the volume of half a sphere is:

V_{hs}=\frac{2}{3}\pi r^3

Since we have 2 half spheres, then the volume of these is the same as the volume of a sphere:

V_{s}=\frac{4}{3}\pi r^3

Then, the composite figure is:

V=\pi r^2 h +\frac{4}{3}\pi r^3 \\ \\ V=\pi r^2(h+\frac{4}{3}r)

The radius of the cylinder is the same of the radius of each half sphere. So:

r=5mm \\ \\ h=10mm \\ \\ \\ V=(3.14) (5)^2((10)+\frac{4}{3}(5)) \\ \\ V=25(3.14)(10+\frac{20}{3}) \\ \\ \boxed{V\approx 1308.33mm^3}

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3 years ago
Place the steps for finding f(x) in the correct order.
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The answer is C
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Sum of two consercutive integers is -49
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The answer is B. Hard to explain but it is B.
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The ideal width of a safety belt strap for a certain automobile is 7 cm. An actual width can vary by at most 0.3 cm. Write an ab
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Trigonometry help!! - double angle formulae
ivolga24 [154]

Answer:

The two rules we need to use are:

Sin(a + b) = sin(a)*cos(b) + sin(b)*cos(a)

cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)

And we also know that:

sin^2(a) + cos^2(a) = 1

To solve the relations, we start with the left side and try to construct the right side.

a) Sin(3*A) = sin (2*A + A) = sin(2*A)*cos(A) + sin(A)*cos(2*A)

sin(A + A)*cos(A) + sin(A)*cos(A + A)

(sin(A)*cos(A) + sin(A)*cos(A))*cos(A) + sin(A)*(cos(A)*cos(A) - sin(A)*sin(A))

sin(A)*cos^2(A) + sin(A)*cos^2(A) + sin(A)*cos^2(A) - sin^3(A)

3*sin(A)*cos^2(A) - sin(A)*sin^2(A)

sin(A)*(3*cos^2(A) - sin^2(A))

Now we can add and subtract 4*sin^3(A)

sin(A)*(3*cos^2(A) - sin^2(A)) + 4*sin^3(A) -  4*sin^3(A)

sin(A)*(3*cos^2(A) + 3*sin^2(A)) - 4*sin^3(A)

sin(A)*3*(cos^2(A) + sin^2(A)) - 4*sin^3(A)

3*sin(A) - 4*sin^3(A)

b) Here we do the same as before:

cos(3*A) = 4*cos^3(A) - 3*cos(A)

We start with:

Cos(2*A + A) =  cos(2*A)*cos(A) - sin(2*A)*sin(A)

= cos(A + A)*cos(A) - sin(A + A)*sin(A)

= (cos(A)*cos(A) - sin(A)*sin(A))*cos(A) - ( sin(A)*cos(A) + sin(A)*cos(A))*sin(A)

= (cos^2(A) - sin^2(A))*cos(A) - sin^2(A)*cos(A) - sin^2(A)*cos(A)

= cos^3(A) - 3*sin^2(A)*cos(A)

=  cos(A)*(cos^2(A) - 3*sin^2(A))

now we subtract and add 4*cos^3(A)

= cos(A)*(cos^2(A) - 3*sin^2(A)) + 4*cos^3(A) - 4*cos^3(A)

= cos(A)*(-3*cos^2(A) - 3*sin^2(A)) + 4*cos^3(A)

= cos(A)*(-3)*(cos^2(A) + sin^2(A)) + 4*cos^3(A)

= -3*cos(A) + 4*cos^3(A)

8 0
3 years ago
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