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tresset_1 [31]
3 years ago
11

Factor the trinomial x^2+10x+16

Mathematics
2 answers:
Amanda [17]3 years ago
7 0
(x + 8)(x + 2)
find 2 numbers that add to 10 and multiply 16
Ulleksa [173]3 years ago
5 0
I believe it’s X^2 + 10x + 41
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A dress which costs $180 is being sold at a discount of 10%. The amount of the discount is
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The discount is $18

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Test pls help! thank you​
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Read 2 more answers
Which values of a, b, and c represent the answer in simplest form?<br> 9/11 divided by 5/11 = a b/c
ozzi

Answer:

a=1, b=9 and c= 5

Step-by-step explanation:

9/11 divided by 5/11

= 9/11 * 11/5

11 gets cancelled

=9/5

it can also be written as 1* 9/5

Hence here a=1, b=9 and c= 5  

<em>Please mark me as brainliest.</em>

3 0
3 years ago
Quit smoking: In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.
Flauer [41]

Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

Test if less than half of HIV-positive smokers have used a nicotine patch:

At the null hypothesis, we test if the proportion is of at least half, that is:

H_0: p \geq 0.5

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

H_1: p < 0.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that \mu = 0.5, \sigma = \sqrt{0.5*(1-0.5)} = 0.5

In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that n = 444, X = \frac{202}{444} = 0.455

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.455 - 0.5}{\frac{0.5}{\sqrt{444}}}

z = -1.9

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

5 0
3 years ago
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