A_n= a₁+(n-1)d
a₁ first term
n terms
d distance between each value
a_n= 12+(405-1)(5)=2032
Answer:
Function B has the greater initial value because the initial value for function A is 4 and the initial value for Function B is 5
Step-by-step explanation:
- <em>The initial value of a function is the output value of the function when the input value is 0</em>
Initial value of A is y=4 at x=0,
and
initial value of B is y=0*6+5= 5 at x=0
Function B has the greater initial value because the initial value for function A is 4 and the initial value for Function B is 5
Each room has 2 walls that are 4x10 = 40 square feet and 2 walls that are 8x10 = 80 square feet. So 80+80+40+40 = 240 square feet of wall will be painted per room.
We use 2 coats of paint so in effect, we double the area. Imagine laying one thin wall on top of the other. The amount of paint area used per room doubles from 240 to 480
There are 4 of these rooms so 4*480 = 1920
The total area we need to paint is 1920 square feet
Divide this over 32 to get 1920/32 = 60
Final Answer: 60
An=Asub1+d(n-1)
Asub5= -5+½(4)
=-5+7
=2
