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o-na [289]
3 years ago
7

Michael and Tyler both ran a half marathon Michael finished in 1 hour 42 minutes and 13 seconds Tyler finished in 97 minutes and

49 seconds who was faster how much faster was he?
Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

Step-by-step explanation:

From the question, we are informed that Michael and Tyler both ran a half marathon and that Michael finished in 1 hour, 42 minutes and 13 seconds while Tyler finished in 97 minutes and 49 seconds.

First, we should know that 60 minutes makes 1 hour, therefore we need to change Tyler's time taken to finish the marathon appropriately. Since Tyler finished in 97 minutes and 49 seconds, this will be converted to 97 minutes equals 1 hour 37 minutes. Therefore, Tyler used 1 hour, 37 minutes and 49 seconds.

Since Michael finished in 1 hour, 42 minutes and 13 seconds while Tyler finished in 1 hour, 37 minutes and 49 seconds. We can see that Tyler is faster than Michael.

To know how much faster Tyler was, we subtract Tyler's time from Michael's. This will be:

= (1 hour, 42 minutes 13 seconds) - (1 hour, 37 minutes, 49 seconds)

= 4 minutes, 24 seconds.

Tyler was faster by 4 minutes, 24 seconds.

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Answer:

29274

Step-by-step explanation:

Because 17*14=238 and 238*123=29274

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A class of 30 is divided into 2 groups such that the size of the smaller group is 2/3 the size of the larger group. How large is
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I kinda did a lil of this in my head so i might not be 100% correct, but i would say the bigger group is 20 and the smaller group is 10

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What is the surface area of a right rectangular prism whose dimensions are 3 feet by 6 feet by 8 feet?
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Can someone help.
r-ruslan [8.4K]

Answer:

m∠C = 38°  (nearest whole number).

Step-by-step explanation:

To find the missing angle, use the Sine Rule.

<u>Sine Rule</u> (for angles)

\sf \dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}

where:

  • A, B and C are the angles
  • a, b and c are the sides opposite the angles

Given:

  • A = 53°
  • a = 18
  • c = 14

To find m∠C, substitute the given values into the formula and solve for C:

\implies \sf \dfrac{\sin 53^{\circ}}{18}=\dfrac{\sin C}{14}

\implies \sf \sin C= \dfrac{14 \sin 53^{\circ}}{18}

\implies \sf C= \sin^{-1} \left( \dfrac{14 \sin 53^{\circ}}{18}\right)

\implies \sf C= 38.40096301...^{\circ}

Therefore, m∠C = 38°  (nearest whole number).

Learn more about the sine rule here:

brainly.com/question/27089170

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5 0
2 years ago
Suppose a family drives at an average rate of 60 mi/h on their way to visit relatives and then an average rate of 40 mi/h on the
hammer [34]

Answer:

Part A) 2 hours

Part B) d/60 hours

Part C) 48 miles/hour

Step-by-step explanation:

Part A) Let "d" be the distance in miles the family traveled to visit their relatives. How many hours did it take to drive there?

we know that

Let

x ----> the time it take on their way to visit relatives in hours

y ---> the time it take on the way back in hours

we know that

The distance of the way to visit is equal to the distance of the way back

The speed multiplied by the time is equal to the distance

so

60x=40y -----> equation A

y=x+1 -----> equation B

substitute equation B in equation A and solve for x

60x=40(x+1)

60x=40x+40

20x=40

x=2 hours

Find the value of y

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The time it take on their way to visit relatives is 2 hours

The time it take on the way back is 3 hours

Part B) In terms of "d," how many hours did it take to drive there?

we have that

The distance is equal to the speed multiplied by the time

d=60x

Solve for x

x=d/60 hours

Part C) Write and solve an equation to determine the distance the family drove to see their relatives. What was the average rate for the entire trip?

To find the average rate for the whole trip we will need the total distance and the total time

The distance of the way to visit is

d=60x

substitute the value of x

d=60(2)=120 miles

so

The total distance is

120(2)=240 miles

we know that the total time is

2 + 3 =5 hours

The average rate for the complete trip is

240/5=48 miles/hour

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