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o-na [289]
3 years ago
7

Michael and Tyler both ran a half marathon Michael finished in 1 hour 42 minutes and 13 seconds Tyler finished in 97 minutes and

49 seconds who was faster how much faster was he?
Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

Step-by-step explanation:

From the question, we are informed that Michael and Tyler both ran a half marathon and that Michael finished in 1 hour, 42 minutes and 13 seconds while Tyler finished in 97 minutes and 49 seconds.

First, we should know that 60 minutes makes 1 hour, therefore we need to change Tyler's time taken to finish the marathon appropriately. Since Tyler finished in 97 minutes and 49 seconds, this will be converted to 97 minutes equals 1 hour 37 minutes. Therefore, Tyler used 1 hour, 37 minutes and 49 seconds.

Since Michael finished in 1 hour, 42 minutes and 13 seconds while Tyler finished in 1 hour, 37 minutes and 49 seconds. We can see that Tyler is faster than Michael.

To know how much faster Tyler was, we subtract Tyler's time from Michael's. This will be:

= (1 hour, 42 minutes 13 seconds) - (1 hour, 37 minutes, 49 seconds)

= 4 minutes, 24 seconds.

Tyler was faster by 4 minutes, 24 seconds.

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No "x" can not be repeated, a function has one x-element and one y-element
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Please help me out!!!!!
notka56 [123]

Answer: D

Step-by-step explanation:

all possible rational zeros are the factors of the last term divided by the coefficient of the first term

so it's (±1, ±3, ±9) / (±1, ±2)

(±1, ±3, ±9) / ±1 = ±1, ±3, ±9

(±1, ±3, ±9) / ±2 = ±1/2, ±3/2, ±9/2

--> ±1, ±3, ±9, ±1/2, ±3/2, ±9/2

8 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
3 years ago
Lee is staying at a hotel. The cost of the first night is $240. The cost for each night after that is $210. Let y represent the
GenaCL600 [577]

A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.

F(1) = 240 +210

F(2) = 240 +2(210)

F(3) = 240+3(210)

.

.

.

.

F(x)= 240 +210x.

Learn more about Sequence:

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3 0
2 years ago
One third of a number Y
vampirchik [111]

Answer:

⅓y

Step-by-step explanation:

\frac{1}{3}  \times y \\  =  \frac{1}{3} y

4 0
3 years ago
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