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o-na [289]
3 years ago
7

Michael and Tyler both ran a half marathon Michael finished in 1 hour 42 minutes and 13 seconds Tyler finished in 97 minutes and

49 seconds who was faster how much faster was he?
Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

Step-by-step explanation:

From the question, we are informed that Michael and Tyler both ran a half marathon and that Michael finished in 1 hour, 42 minutes and 13 seconds while Tyler finished in 97 minutes and 49 seconds.

First, we should know that 60 minutes makes 1 hour, therefore we need to change Tyler's time taken to finish the marathon appropriately. Since Tyler finished in 97 minutes and 49 seconds, this will be converted to 97 minutes equals 1 hour 37 minutes. Therefore, Tyler used 1 hour, 37 minutes and 49 seconds.

Since Michael finished in 1 hour, 42 minutes and 13 seconds while Tyler finished in 1 hour, 37 minutes and 49 seconds. We can see that Tyler is faster than Michael.

To know how much faster Tyler was, we subtract Tyler's time from Michael's. This will be:

= (1 hour, 42 minutes 13 seconds) - (1 hour, 37 minutes, 49 seconds)

= 4 minutes, 24 seconds.

Tyler was faster by 4 minutes, 24 seconds.

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Answer:

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Step-by-step explanation:

A) 1 divided by 9=0.11111111

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Look at the circle you created that has point C (the midpoint of AB) as its center and passes through point A. What can you say
Mice21 [21]

The inscribed angle on the circumference of the circle subtended by the diameter at the center is a right angle

What can be said about segment AB is; Segment AB is the diameter of circle with midpoint at C

What can be said about angle BDA is; Angle BDA is an inscribed angle of the circle with midpoint at C, subtended by the diameter AB at the center

The measure of angle BDA is 90°

What can be said about angle BEA is; Angle BEA is an inscribed angle of the circle with midpoint at C, subtended by the diameter AB at the center

The measure of angle BEA is 90°

The given diagram shows;

Circle with midpoint <em>C</em>, along AB, and radius AC

The diameter of circle C = AB

Circle with midpoint <em>A</em>, intersecting with circle <em>C</em> at points <em>D</em> and <em>E</em>

Tangents from point B on circle, <em>C</em>, intersect with circle <em>A</em> at points <em>D</em> and <em>E</em>

<em> </em>

Required parameters;

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The segment AB is a line that intersects the circle <em>C</em> at two points and also passes through the the point <em>C</em> which is the center of the circle <em>C</em>

Therefore, the segment AB is the diameter of the circle with center at <em>C</em>

  • What can be said about angle BDA

The angle BDA is the inscribed angle of circle <em>C</em> subtended by the points <em>A</em> and <em>B</em> which specifies the diameter of the circle with midpoint <em>C</em>

Therefore, the angle BDA is subtended by the diameter of the circle at the center

According to circle theorem, we have;

Angle subtended at the center = 2 × The angle subtended at the circumference

The angle subtended at the center by the diameter AB = 180° (Angle on a straight line)

Therefore;

The angle subtended at the center = 180° = 2 × Angle BDA

Angle BDA = 180°/2 = 90°

Angle BDA  = 90°

  • What can be said about angle BEA

Similarly, we have;

The angle subtended at the center = 180° = 2 × Angle BEA

Angle BEA = 180°/2 = 90°

Angle BEA = 90°

Find out more about inscribed angles of a circle here:

brainly.com/question/17021375

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2 years ago
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Step-by-step explanation:

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