Answer:
Number of bacteria after 100 days is 1237.
Step-by-step explanation:
Since bacterial growth is a geometrical sequence.
Therefore, their population after time t will be represented by the expression

Where a = first term of the sequence
r = common ratio of the sequence
n = duration or time
Since first term of the sequence = number of bacteria in the start = 1
Common ratio = r = (1 + 0.04) = 1.04
![S_{100}=\frac{1[(1.04)^{100}-1)]}{1.04-1}](https://tex.z-dn.net/?f=S_%7B100%7D%3D%5Cfrac%7B1%5B%281.04%29%5E%7B100%7D-1%29%5D%7D%7B1.04-1%7D)
= 
= 1237.64 ≈ 1237 [Since bacteria can't be in fractions]
Therefore, number of bacteria after 100 days is 1237.
<h3>Given:</h3>
<h3>To find:</h3>
How much is $100 in ZA rands.
<h3>Solution:</h3>
Let the unknown be "x"

We'll have to do cross multiplication.
So we'll have to multiply 100 and 17.


<u>T</u><u>herefore</u><u>,</u><u> </u><u>$</u><u>1</u><u>0</u><u>0</u><u> </u><u>is</u><u> </u><u>1</u><u>7</u><u>0</u><u>0</u><u> </u><u>ZA</u><u> </u><u>rands</u><u>.</u>
Answer: y=3/4x + 1/2
Step-by-step explanation: Parallel lines must have the same slope, so you already know the equation must be something like y=3/4x+b. You are given a point that the line goes thru(2,2), so you can plug this point into the equation to solve for b.
(2)=3/4(2) + b
2=6/4 + b
2= 3/2 + b
b= 2-3/2
b=4/2- 3/2
b=1/2
so y=3/4x + 1/2
The answer is 11 & 51/100!