go that much "clockwise", you'll end up at the 2nd quadrant,
the reference angle, is its reflective angle on the 1st quadrant
We use the following trigonometric identity to answer the question:
sin^ 2 (theta) + cos^ 2 (theta) = 1
We substitute the values:
sin ^ 2 (theta) + 0.73 = 1
We cleared:
sin ^ 2 (theta) = 1-0.73
sin ^ 2 (theta) = 0.27
Answer:
a possible value of sin ^ 2 (theta) is:
c.0.26 (nearest option)
Step-by-step explanation:
according to question triangle is concurrent so two traingle= 1rectangle
so finally ans is 6×2(12+2)=168
Answer:
(6,6)
Step-by-step explanation:
3x+5y=48
-3x+5y=12
Ok so when you're doing elimination you want to combine all of the like terms. In this case, we need to combine 3x and -3x, 5y and 5y, and 48 and 12. 3x and -3x cancel out, so that leaves you with 10y=60. Solving for y gives you y=6. Now you need to solve for x, so using 3x+5y=48, by plugging in y you get 3x+(5*6)=48. Simplifying that gives you 3x+30=48. Subtract 30 and divide by 3, and you get x=6. Thus the Answer is (x,y) or (6,6)
