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3 years ago

What is the result of 5/6 + 2/3

1 answer:

4 0

You can convert 2/3 into a fraction that makes adding a lot easier.

Since 3 times 2 is equal to 6, you can multiply the numerator and denominator of 2/3 by 2 to get 4/6.

From there, you add 4/6 + 5/6 to get 9/6.

Since both 9 and 6 are divisible by 3, you can simplify the fraction to 3/2.

Your final answer would be 3/2
Which can also be formatted as 1 1/2 or 1.5

You might be interested in

A business’s assets are valued at $600,000, and the value depreciates 20% per year. Using the formula V(t) = V0(b)t, what is V0,

Nana76 [90]

The formula is
V (t)=V0(b)^t
V (t) the value of the assets after 5 (t) years ?
V0 current value of assets 600000
B=1-0.20=0.8
T 5 years

So the value of assets after 5 years is
V (5)=600,000×0.8^(5)=196,608

7 0

3 years ago

Which expression is equivalent to x^6-9

svlad2 [7]

Answer: (x^3)^2 - 3^2

Step-by-step explanation:

6 0

3 years ago

The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the nu

inessss [21]

The numbers are 4,8, and 14 because 4+8+14=26 an 4x2=8 and 8+6=14

7 0

3 years ago

What is the percent / degree of X ?

tia_tia [17]

Answer: 65

Step-by-step explanation:

All those angles added up have to equal 360 degrees.

The little square on the angle to the left of x means that it's a right angle, or 90 degrees.

360

- 180

= 180 <--- this is the bottom half,

180

- 90 <--- the right angle on the left

= 90

-25

= 65 <--- that's x

8 0

2 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

$\mu_s=np=500*0.90=450$

The standard deviation will be:

$\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7$

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

$z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932$

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

$\mu=np=300*0.932=279.6$

The standard deviation will be:

$\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36$

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

$P(270\leq x\leq280)=P(269.5$

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

$P(X=280)=P(279.5$

8 0

3 years ago