The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 12.8° If skyscraper B is 1479

Question

3 years ago

5

The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 12.8° If skyscraper B is 1479

feet tall how far apart are the two
skyscrapers? Assume the bases of the two buildings are at the same elevation.
feet.
The distance from skyscraper A to skyscraper B is
(Round to two decimal places as needed.)

Mathematics

1 answer:

melisa1 [442] · Answer 1 · 2022-01-14T17:03:01+03:00

melisa1 [442]3 years ago

6 0

Answer:

6509.84 ft to the nearest hundredth.

Step-by-step explanation:

We have a right triangle in which the opposite side is 1479 ft and we need to find the adjacent side:

Tan 12.8 = opposite / adjacent side

tan 12.8 = 1479/ x

x = 1479/tan 12.8

= 6509.84 ft.