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worty [1.4K]
3 years ago
5

The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 12.8° If skyscraper B is 1479

feet tall how far apart are the two
skyscrapers? Assume the bases of the two buildings are at the same elevation.
feet.
The distance from skyscraper A to skyscraper B is
(Round to two decimal places as needed.)
Mathematics
1 answer:
melisa1 [442]3 years ago
6 0

Answer:

6509.84 ft to the nearest hundredth.

Step-by-step explanation:

We have a right triangle in which the opposite side is 1479 ft and we need to find the adjacent side:

Tan 12.8 = opposite / adjacent side

tan 12.8 = 1479/ x

x = 1479/tan 12.8

= 6509.84 ft.

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In the figure, triangle CAE is an enlargement of triangle CBD with scale factor of 4/3. The area of the smaller triangle is 9cm2
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Answer:

16 cm^2

Step-by-step explanation:

Given

\triangle CAE -- Bigger Triangle

\triangle CBD -- Smaller Triangle

k = \frac{4}{3} --- Scale factor

Area of CBD = 9

Required

Determine the area of CAE

The area of triangle CBD is:

A_1 = \frac{1}{2}bh

\frac{1}{2}bh = 9

The area of CAE is:

A_2 = \frac{1}{2}BH

Where:

B = \frac{4}{3}b and

H = \frac{4}{3}h

The above values is the dimension of the larger triangle (after dilation).

So, we have:

A_2 = \frac{1}{2}*\frac{4}{3}b * \frac{4}{3} * h

A_2 = \frac{1}{2}*\frac{4}{3} * \frac{4}{3} *b* h

A_2 = \frac{1}{2}*\frac{16}{9}  *b* h

Re-order

A_2 = \frac{16}{9}*\frac{1}{2}* b* h

A_2 = \frac{16}{9}*\frac{1}{2}bh

Recall that:

\frac{1}{2}bh = 9

A_2 = \frac{16}{9}*9

A_2 = 16

Hence, the area is 16 cm^2

3 0
3 years ago
Under his cell phone plan Jason pays a flat cost of $60.50 per month and four dollars per gigabyte he wants to keep his bill at
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Answer:

2 gigabytes of data

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Given

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Answer:

A

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