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2 years ago

Plz help will mark brainless if right answer ;)

Mathematics

2 answers:

Pavel [41]2 years ago

7 0

Answer:

Step-by-step explanation:

Since each triangle is an equilateral triangle all side are the same length. Thus, one side is 15/3=5 inches. The perimeter of the entire figure would then be 3x6=18 since there are 6 sides.

uysha [10]2 years ago

4 0

Answer: i think b

Step-by-step explanation: if incorrect so so so sorry

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Evaluate the double integral.

Fynjy0 [20]

Answer:

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

Step-by-step explanation:

The equation of the line through the point $(x_o,y_o)$ & $(x_1,y_1)$ can be represented by:

$y-y_o = m(x - x_o)$

Making m the subject;

$m = \dfrac{y_1 - y_0}{x_1-x_0}$

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

$m= \dfrac{2-1}{1-0}$

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

$m = \dfrac{1-2}{4-1}$

$m = \dfrac{-1}{3}$

∴

$y-2 = -\dfrac{1}{3}(x-1)$

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

$\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg) dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ([y^2(-4y+8)] \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( -4y^3+8y^2 \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{-45+56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{11}{3}\bigg]$

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

4 0

1 year ago

1 (66 divided by 6)+31"

Juliette [100K]

Answer:

1. 42

2. 6

3. 18

4. 0

5. - 2

Step-by-step explanation:

Use BIDMAS

6 0

2 years ago

What is the slope of the line through (-7.-8) and (0.4)?

Dmitry_Shevchenko [17]

Use the equation (x2-x1)/(y2-y1)

Substitute the value of x and y

7 0

2 years ago

Grace, Chelsea, and Roan are simplifying the same polynomial expression. Which

Alexus [3.1K]

Answer:

Hey there!

3(2 - x) - 2(6x - 8)

6-3x-12x+16

6-15x+16

-15x+22

Hope this helps :)

6 0

2 years ago

3. Factory farming funk - The US Environmental Protection Agency (EPA) recently reported that confined animal feeding operations

Vikentia [17]

Answer:

Step-by-step explanation:

Hello!

There was a survey made in Michigan asking the residents if they were in favor of or against the creation of standards to limit pollution by CAFOs.

Using the results of the survey the student that conducted it estimated the population proportion of Michigan residents that are in favor of the creation of standards to limit pollution by CAFOs.

The calculated 95% CI is [0,7752; 0,8248]

Interpretation: With a 95% confidence level you'd expect that the interval [0,7752; 0,8248] will include the true population proportion of Michigan residents that are in favor of the creation of standards to limit pollution by CAFOs.

i.e. If you were to construct 100 confidence intervals, you'd expect 95 of them to contain the true value of the proportion of Michigan residents that are in favor of the creation of standards to limit pollution by CAFOs.

With this in mind:

Consider all of the following statements and determine which among them is incorrect

1) There is a 95% probability that the actual percent of Michigan residents in favor of pollution standards is between 77.52% and 82.48%. INCORRECT

2) Approximately 95% of MSU students favor pollution standards at a rate of 77.52% and 82.48%. INCORRECT

The confidence level is the probability that the interval will contain the true value of the parameter of interest and the bonds of the interval indicate the possible range of that parameter.

Also in 1) The parameter is not defined correctly, and in 2) the population of interest is incorrect.

3) If this study were repeated many times, we'd expect approximately 95% of future confidence intervals to contain the true rate at which Michigan residents favor the creation of pollution standards. CORRECT

4) With 95% confidence, we estimate the true rate at which Michigan residents favor the creation of pollution standards to be between 77.52% and 82.48%. CORRECT

I hope it helps!

6 0

2 years ago