Solve (4x^2-1)(x^2+2)
1 answer:
You might be interested in
Answer:
option 4. The graph has zeroes at x = 15 an x = -15 and it opens upward.
Step-by-step explanation:
we have
This is the equation of a vertical parabola open upward (the leading coefficient is positive)
The vertex represent a minimum
The vertex is the point (0,-225)
The axis of symmetry is x=0 (y-axis)
Find the x-intercepts (values of x when the value of y is equal to zero)
For y=0
square root both sides
therefore
The graph has zeroes at x = 15 an x = -15 and it opens upward.