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Gre4nikov [31]
3 years ago
12

Last question of the section

Mathematics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

SA of black base: 84 cm^2

SA of blue faces: 84 cm^2

SA of gold faces: 60.2 cm^2

SA of 1 ornament: 228.2 cm^2

SA of 100 ornaments: 22,820 cm^2

Step-by-step explanation:

SA of black base:

A = lw

A = 7(12)

A = 84 cm^2

SA of blue faces:

A = bh

(don't divide by 2 since there are 2 triangles)

A = 12(7)

A = 84 cm^2

SA of gold faces:

A = 7(8.6)

(don't divide by 2 since there are 2 triangles)

A = 60.2 cm^2

SA of 1 ornament:

Add #s in bold:

84 + 84 + 60.2 = 228.2 cm^2

SA of 100 ornaments:

Multiply SA of 1 ornament by 100:

228.2(100) = 22,820 cm^2

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Answer:

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Step-by-step explanation:

6 0
3 years ago
What's the slope of (-4,7)(-2,17)
yaroslaw [1]
Given two points (x₁,y₁) and (x₂,y₂) the slope of the line passes through these points will be:

m=(y₂-y₁)/(x₂-x₁)

Data:
The points are (-4,7) and (-2,17), then the slope will be:
m=(17-7)/(-2+4)=7/2

Answer: the slope of the line passes through these points would be 7/2
7 0
3 years ago
Read 2 more answers
-6x + 5y = 1<br> 6x + 4y = –10
Firlakuza [10]

Answer:

x=-1

y=-1

Step-by-step explanation:

-6x + 5y =1 ......equation (1)

6x + 4y = –10 ......equation (2)

adding equation (1) to equation (2)

9y=-9

9y/9 =-9/9 (dividing both side by the coefficient of y)

y=-1

subtituting the value of y =-1 into equation (2)

6x+4(-1)=-10

6x+(-4)=-10

6x-4=-10

6x=-10+4(making constant to be at one side and the variable at the other side)

6x=-6

x=-6/6

x=-1

8 0
4 years ago
52 cards what is the probability that a card drawn is a diamond
irina [24]

Answer:

1/4 or 25%

Step-by-step explanation:

there are four different suits in total in a card deck. There is an even amount of each one (Diamonds, Spades, Clubs, Hearts). Therefore, you have a 1 in four chance- or a 25% chance of drawing a diamond.

5 0
3 years ago
Read 2 more answers
I need help! Please help me! :(
sergey [27]

Let's go one by one.

A: The distribution is, in fact, symmetric.  I know this because if I were to draw a straight line, or hold up a mirror to the screen, both sides would match.

B: B is not true because there is only student who is the maximum age of 16, as compared to the majority of students who are 14.

C: Let's write down the data:

12, 13, 13, 14, 14, 14, 14, 14, 14, 15, 15, 16

If we add all these up, we get 168. We then should divide by 12, the amount of data samples, which gives us 14.

The mean is 14.

Automatically, I see that the center is filled with 14. Even though there are 12 total data pieces, we will not need to find the middle of two of the numbers-because 14 and 14 are the same number.

The median is 14.

Because the mean and median are both 14, we can conclude that C is true.

D: Because the mode (or most common number) would also be 14, we can conclude instantly that the 14 we got from the mean and median is the best representation of students in the play. D is also true.  As far as the best measure of center goes, I usually prefer the mean, but it is almost entirely situational.

1. Mean (The average is<u> almost</u> always reliable)

Non-example: (4,4,4,4,4,4,4,4,4,4,307) It is clear there is an outlier here, which could affect the data more than it needs to-therefore this is a non-example.

Please let me know if this was helpful, or if you have any questions! If you are able, I'd be grateful to receive a rating!

6 0
3 years ago
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