A line has a slope of -6 and passes through the point (2, 3). What is its equation in

1 answer:

3 0

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{3})~\hspace{10em} \stackrel{slope}{m}\implies -6 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-6}(x-\stackrel{x_1}{2}) \\\\\\ y-3=-6x+12\implies y=-6x+15$

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Answer:

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since they're both in standard form, its easier to do the process of elimination

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