Answer:
Total number of ways will be 209
Step-by-step explanation:
There are 6 boys and 4 girls in a group and 4 children are to be selected.
We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.
So the groups can be arranged as
(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)
Now we will find the combinations in which these arrangements can be done.
1 Boy and 3 girls = 
=24
2 Boy and 2 girls=
3 Boys and 1 girl = 
4 Boys = 
Now total number of ways = 24 + 90 + 80 + 15 = 209
angle AOB = 132 and is also the sum of angles AOD and
DOB. Hence
angle AOD + angle DOB = 132° ---> 1
angle COD = 141 and is also the sum of angles COB and BOD. Hence
angle COB + angle DOB = 141° ---> 2
Now we add the left sides together and the right sides of equations 1 and 2
together to form a new equation.
angle AOD + angle DOB + angle COB + angle DOB = 132 + 141 ---> 3
We should also note that:
angle AOD + angle DOB + angle COB = 180°
Therefore substituting angle AOD + angle DOB + angle COB in equation 3 by 180
and solving for angle DOB:
180 + angle DOB = 132 + 141
angle DOB = 273 - 180 = 93°
(3x-4)(5x^2-2x+6)
15x^3-6x^2+18x-20x^2+8x-24
15x^3-26x^2+26x-24
5/54 this should be your answers hope this helps
Since we have a transverse line that cuts through the straight line parallel to the height, then we can see that the angles are divided into two sections.
We also have vertically opposite angles, since the angle sum of a straight line is 180°. We have perpendicular lines since we are given a 90° angle. Thus, we know the missing angle is 45°.
Thus, 45 + x = 180
x = 135°
