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Sedaia [141]
2 years ago
10

Prove: AB ≅ CD URGENT HELP NEEDED

Mathematics
1 answer:
alina1380 [7]2 years ago
4 0

Answer:

Down Here

Step-by-step explanation:

Step 2:

Statement: m∠AEB ≅ m∠ CED

Reason: Vertical Angles

Step 3:

Statement: BE = DE

Reason: Def. of bisect

Step 4:

Statement: AE = CE

Reason: Def. of bisect

Step 5:

Statement: ΔAEB ≅ ΔCED

Reason: SAS

Step 6:

Statement: AB = DC

Reason: CPCTC (congruent parts of congruent traingles are congruent)

-Chetan K

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It is true that the product of two consecutive even integers are always one less than the square of their average.

<u>Step-by-step explanation</u>:

Let the two consecutive odd integers be 1 and 3.

  • The product of 1 and 3 is (1\times3)=3
  • The average of 1 and 3 is (1+3)/2 =4/2 = 2
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∴ The product 3 is one less than the square of their average 4.

Let the two consecutive even integers be 2 and 4.

  • The product of 2 and 4 is (2\times4)=8
  • The average of 2 and 4 is (2+4)/2 =6/2 = 3
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∴ The product 8 is one less than the square of their average 9.

Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.

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Step-by-step explanation:

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Solve for x<br> -2/5x - 8/15x + 1/3x = -54<br> x=?
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Answer:

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Step-by-step explanation:

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Write the Slope-Intercept and Point-Slope forms of the line passing through the point (-3, 2) and having a slope of -4/5
weeeeeb [17]

Answer:

slope-intercept: y=\frac{-4}{5} x-\frac{2}{5}

point-slope: y-2=\frac{-4}{5} (x+3)

Step-by-step explanation:

The slope-intercept form of a line is written as y = mx + b, where m is the slope and b is the y-intercept.

The point-slope form of a line is written as y - y1 = m(x - x1), where (x1, y1) is a given point and m is the slope.

Here, we see that the slope is -4/5, which means that m = -4/5. Since we're given a point (-3, 2), let's go ahead and just write the point-slope form already. (x1, y1) = (-3, 2) so x1 = -3 and y1 = 2. Then:

y - y1 = m(x - x1)

y - 2 = (-4/5) * (x + 3)

y-2=\frac{-4}{5} (x+3)

Now, we want to find the slope-intercept form, so we need to figure out the y-intercept. Well, first, let's plug in what we know:

y = mx + b

y = (-4/5)x + b

Any point on this line will satisfy the above equation. Since (-3, 2) is on this line, if we plug -3 in for x and 2 in for y, the equation should hold true, so we can solve for b:

y = (-4/5)x + b

2 = (-4/5) * (-3) + b

2 = 12/5 + b

b = -2/5

So, the y-intercept is -2/5. Then the slope-intercept form is:

y=\frac{-4}{5} x-\frac{2}{5}

Thus, our two equations are:

slope-intercept: y=\frac{-4}{5} x-\frac{2}{5}

point-slope: y-2=\frac{-4}{5} (x+3)

8 0
2 years ago
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