Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
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Explanation:</h2><h2>
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Let's solve this problem graphically. Here we have the following equation:

So we can rewrite this as:

So the solution to the equation is the x-value at which the functions f and g intersect. In other words:

Using graphing calculator, we get that this value occurs at:

Answer:
Mean: 41.8
Median:41
Mode:27
Range:46
Step-by-step explanation:
C) More girls than boys prefer hamburgers over hotdogs.
The explicit formula for this arithmetic sequence is A(n)=1/2•(-8)^(n-1)