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Misha Larkins [42]
3 years ago
8

Show cos 20 * cos 40 * cos 80 =1/8

Mathematics
1 answer:
Delicious77 [7]3 years ago
8 0
 cos 20 cos 40 cos 80 = 
= ( 2 sin 20 cos 20 cos 40 cos 80 ) / 2 sin 20 =
( multiple and divide by 2 sin 20 )
= ( sin 40 cos 40 cos 80 ) / 2 sin 20 =
= ( 1/2 sin 80 cos 80 ) / 2 sin 20 = 
= ( sin 80 cos 80 ) / 4 sin 20 = 
= 1/2 sin 160 / 4 sin 20 = 
= sin 160 / 8 sin 20 =  ( and since:  sin 160 = sin 20 )
= 1 / 8 
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When you factor the equation...

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Using the asymptote concept, we have that:

  • The vertical asymptote is x = 9.
  • The horizontal asymptote is y = 3.
  • The end behavior is that as x \rightarrow \infty, y \rightarrow 3.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

f(x) = \frac{3x}{x - 9}

For the vertical asymptote, we have that:

x - 9 = 0 -> x = 9.

For the horizontal asymptote:

y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{3x}{x - 9} = \lim_{x \rightarrow \infty} \frac{3x}{x} = \lim_{x \rightarrow \infty} 3 = 3

Hence, the end behavior is that as x \rightarrow \infty, y \rightarrow 3.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

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61.5 or 61 and one half
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