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Jlenok [28]
3 years ago
10

What is the nth term of 12 10 8 6 4 ?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

-4

Step-by-step explanation:

The difference from each number is 2 so u keep subtracting 2 from each term until u get to the nth term. For ex: 12-2=10, 10-2=8, 8-2=6...

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Because the proportional relation is defined by k = \frac{y}{x}. If ratio is \frac{units}{1unit} then it is a rate. Unit rate means per 1 unit such as \frac{amountofmoney}{1kg} or \frac{km}{1hour} thus the correct answer is A.

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Simplify -x - 2 + 15x
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Read 2 more answers
A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second. The function h(t)=−16t2+55t+4
kramer

<u>Given</u>:

A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second.

The function h(t)=-16t^2+55t+4 represents the height h(in feet) of the ball after t seconds.

We need to determine the time of the ball at which it is 30 feet above the ground.

<u>Time:</u>

To determine the time that it takes for the ball to reach a height of 30 feet above the ground, let us substitute h(t) = 30, we get;

30=-16t^2+55t+4

26=-16t^2+55t

Adding both sides of the equation by 16t², we get;

16t^2+26=55t

Subtracting both sides of the equation by 55t, we have;

16t^2-55t+26=0

Let us solve the quadratic equation using the quadratic formula, we get;

t=\frac{-(-55) \pm \sqrt{(-55)^2-4(16)(26)}}{2(16)}

t=\frac{55 \pm \sqrt{3025-1664}}{32}

t=\frac{55 \pm \sqrt{1361}}{32}

t=\frac{55 \pm 36.89}{32}

t=\frac{55 + 36.89}{32} \ or \ t=\frac{55- 36.89}{32}

t=\frac{91.89}{32} \ or \ t=\frac{18.11}{32}

t=2.9 \ or \ t=0.6

The value of t is t = 0.6 because this denotes the time taken by the ball to reach a height of 30 feet from the ground.

Therefore, the time taken by the ball to reach a height of 30 feet above the ground is 0.6 seconds.

5 0
3 years ago
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