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NISA [10]
3 years ago
13

Can someone help me simplify: (x^5/6^2)^3? I know how to solve these kind of problems, but only when the bases are the same. Ple

ase include steps and work. I’m giving away as much points as possible. Thank you
Mathematics
2 answers:
Elden [556K]3 years ago
7 0

(x^5/6^2)^3

Distribute the exponent 3 to both numbers. Multiply the exponents by 3. 5•3=15 and 2•3=6

x^15/6^6

You can find the answer to 6^6, it’s 36.

x^15/36

If you have any further questions feel free to ask.

Hope this helps.

Diano4ka-milaya [45]3 years ago
3 0

Answer:

Step-by-step explanation:

(x^5/6^2)^3

Distribute the exponent 3 to both numbers. Multiply the exponents by 3. 5•3=15 and 2•3=6

x^15/6^6

You can find the answer to 6^6, it’s 36.

x^15/36

If you have any further questions feel free to ask.

Hope this helps.

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An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio
Rudik [331]

Answer:

a) E(y) = 0.8

b) The average subcharge is $165

Step-by-step explanation:

We are given the following distribution in the question:

y:           0        1        2         3

P(y):   0.50   0.25   0.20   0.05

a) E(y)

E(y) = \displaystyle\sum y_iP(y_i)\\\\E(y) = 0(0.50)+1(0.25)+2(0.20)+3(0.05)\\E(y) = 0.8

b) Expected value of subcharge

Subcharge =

\$110y^2

Expected value of subcharge =

=110E(y^2)\\\\=110\displaystyle\sum y_i^2P(y_i)\\\\=110(0^2(0.50)+1^2(0.25)+2^2(0.20)+3^2(0.05))\\=110(1.5)=165

Thus, the average subcharge is $165

5 0
3 years ago
Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'
AleksandrR [38]
Let's start by assuming Armando's house is between Joey's and the park. 

Let x be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park. 

</span>\dfrac{9}{10} = x + \dfrac{3}{5}

x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}

That's probably the answer they're looking for.  But what if the park is between Joey and Armando's houses or Joey is between the park and Armando?  (The latter isn't really possible with the given distances.)

Let a, b, c be the distances between three collinear points like we have here.  Our equation is really a few equations in one, something like

\pm a \pm b = \pm c

Let's get rid of the plus/minuses. Squaring,

a^2 + b^2\pm 2ab = c^2

\pm 2ab = c^2-a^2-b^2

4a^2b^2 = (c^2-a^2-b^2)^2

For us, that's a quadratic equation for c^2

4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2

I'll skip right to the solutions,

c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}


c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

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4 years ago
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<span>The correct answer is option C. i.e. Statements 1 and 2 are postulates because they are true facts.A line must contain atleast two point because then only line can be formed. Similarly, a plane is formed when there are atleast three non-collinear points.</span>
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Find Each Sum.<br> (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =
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To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.

<span>(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) 
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4c² + 11cd + 5d
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