Answer:
- Leaves impurities in their starting layer - Extraction
- Moves impurities from one layer to another - Wash
- Moves desired compound from one layer to another - Extraction
- Often involves a reaction in one of the layers - Extraction
- Leaves desired compound in its starting layer - Wash
Explanation:
Both extraction and wash are technical materials separation processes. Both seek to carry out a separation of liquid-liquid, through the relationship between solvent and solute present in this solution. Both use a separation funnel and are very similar processes where the main difference is the purpose that each one seeks to exercise. The extraction causes the dissolution of the material that the researcher wants to leave behind. this process leaves impurities in the initial solution layer and moves the researcher's desired compound to the second layer of solution. A chemical reaction can take place during this process.
A wash, on the other hand, dissolves all impurities from the solution and extracts the compound desired by the researcher. Therefore, we can conclude that during this process the impurities are moved from one layer to another in the solution until it is discarded from the funnel, leaving the desired compound in the initial layer.
Answer:
The key to understanding water's chemical behavior is its molecular structure. A water molecule consists of two hydrogen atoms bonded to an oxygen atom, and its overall structure is bent. This is because the oxygen atom, in addition to forming bonds with the hydrogen atoms, also carries two pairs of unshared electrons
Explanation:
Hope it helps
Answer: V2= 41.2mL
Explanation:
Givens:
* V1= 20ml
* T1 = -109 ⁰C --> K= ⁰C + 273.15 --> 164.15 K
* V2 = ??
* T2= 338.15 K
Use Charles law V1/T1 = V2/T2
Since we are looking for V2 we can rearrange the formula to
V2= (T2 x V1) /T1
V2= (338.15K x 20mL) / 164.15 K
V2= 41.2mL
NOTE:
Temperature should always be in K not in ⁰C or ⁰F
To convert from C to K use
*K= ⁰C + 273.15
Enter your C value in the ( ⁰C ) and you can get K
Answer:
B. Its direction changes, it's speed changes, and it's wave length changes.
Explanation:
If not, I'm sorry I'm not that smart or it might be d. I don't know
Answer:
b) The dehydrated sample absorbed moisture after heating
Explanation:
a) Strong initial heating caused some of the hydrate sample to splatter out.
This will result in a higher percent of water than the real one, because you assume in the calculation that the splattered sample was only water (which in not true).
b) The dehydrated sample absorbed moisture after heating.
Usually inorganic salts may absorbed moisture from the atmosphere so this will explain the 13% difference between calculated water percent the real content of water in the hydrate.
c) The amount of the hydrate sample used was too small.
It will create some errors but they do not create a difference of 13% difference as stated in the problem.
d) The crucible was not heated to constant mass before use.
Here the error is small.
e) Excess heating caused the dehydrated sample to decompose.
Usually the inorganic compounds are stable in the temperature range of this kind of experiments. If you have an organic compound which retain water molecules you may decompose the sample forming volatile compounds which will leave crucible so the error will be quite high.