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goldfiish [28.3K]
3 years ago
11

If an equal mass of sugar and aluminum were poured into separate containers, which would require the smaller container?

Chemistry
2 answers:
kirill115 [55]3 years ago
8 0

Aluminium requires the smaller container !

Solnce55 [7]3 years ago
5 0

Answer:

Aluminum

Explanation:

It is given that:

Mass of sugar = Mass of aluminum

The volume occupied by the two substances can be deduced from their densities.

Density of a substance is a constant and given by the ratio of its mass to volume.

Density = \frac{Mass}{Volume}

Volume = \frac{Mass}{Density}

Density of aluminum = 2.7 g/cm3

Density of Sugar = 1.59 g/cm3

Since the masses are equal we have:

\frac{Volume\ Aluminum}{Volume\ Sugar} = \frac{Density\ sugar}{Density\ Aluminum} = \frac{1.59}{2.7} = 0.59

Volume of Aluminum = 0.59 (Volume of sugar)

Therefore, aluminum will require a container of smaller volume

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5ml * 0.01 mol/L *1L/1000mL = 5x10^-5 moles

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To solve the molar heat we need to find the moles of KNO3 dissolved and the change in heat as follows:

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10.6g * (1mol/101.1032g) = 0.1048 moles KNO3

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