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goldfiish [28.3K]
3 years ago
11

If an equal mass of sugar and aluminum were poured into separate containers, which would require the smaller container?

Chemistry
2 answers:
kirill115 [55]3 years ago
8 0

Aluminium requires the smaller container !

Solnce55 [7]3 years ago
5 0

Answer:

Aluminum

Explanation:

It is given that:

Mass of sugar = Mass of aluminum

The volume occupied by the two substances can be deduced from their densities.

Density of a substance is a constant and given by the ratio of its mass to volume.

Density = \frac{Mass}{Volume}

Volume = \frac{Mass}{Density}

Density of aluminum = 2.7 g/cm3

Density of Sugar = 1.59 g/cm3

Since the masses are equal we have:

\frac{Volume\ Aluminum}{Volume\ Sugar} = \frac{Density\ sugar}{Density\ Aluminum} = \frac{1.59}{2.7} = 0.59

Volume of Aluminum = 0.59 (Volume of sugar)

Therefore, aluminum will require a container of smaller volume

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Answer: PCl₃O

Explanation:

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2) You use the chemical symbol for each kind of atom (element) and subscripts to the right of each symbol to tell the number of atoms of each element.

3) For example, O₂ means two atoms of oxygen. Al₂O₃ means two atoms of aluminum and 3 atoms of oxygen.

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Hence, PCl₃O is the chemical formula of your compound.

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3 years ago
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hat is the pH of a solution with a hydroxide ion concentration of 10–6M? A. pH = 12 B. pH = 8 C. pH = 6 D. pH = 7
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pH=14-pOH

pOH=-lg[OH⁻]

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3 years ago
Nitric oxide, NO, is made from the oxidation of NH3, and the reaction is represented by the equation: 4NH3 + 5O2 → 4NO + 6H2O Wh
tamaranim1 [39]

Answer:

16.16g of O2.

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We'll begin by writing the balanced equation for the reaction. This is illustrated below:

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Next, we shall determine the mass of NH3 and O2 that reacted from the balanced equation. This is illustrated below:

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Mass of O2 from the balanced equation = 5 x 32 = 160g.

From the balanced equation above,

68g of NH3 reacted with 160g of O2.

Now, we can calculate the mass of O2 that will be required to react completely with 6.87 g of NH3. This is illustrated below:

From the balanced equation above,

68g of NH3 reacted with 160g of O2

Therefore, 6.87g of NH3 will react with = (6.87 x 160)/68 = 16.16g of O2.

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Answer:

Explanation:

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A controlled variable is the variable that is left constant throughout the course of an experiment. The controlled variable here is the gender.

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