Answer:
The answer is "5.18 ".
Explanation:
It's a question of chemistry. Therefore, the following solution is provided:
We will first determine the solution's pOH. The following can possible:
The concentration of Hydroxide ion
Furthermore, the pH of the solution shall be established. It was provided as follows:
When collecting all the like terms:
Therefore, the solution of pH is 5.18.
Potassium and Nitrate ions are spectator ions in the reaction:
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Ions that are not involved in the actual chemical reaction are called spectator ions.
A precipitation reaction occurs when two ionic compounds react to produce a precipitate and an insoluble substance which stays in the solution as a spectator ion.
Hence, Potassium and Nitrate ions are spectator ions in the reaction:
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Learn more about the spectator ions here:
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Answer:
See explanation below
Explanation:
The malonic ester synthesis is a commonly used reaction to form several products. In this case when we have an excess of base, in presence of an alkyl halide of 4 carbons, this will promoves the formation of a ring.
This synthesis has 4 steps:
1) Enolate formation. In this step the strong base (Such as methoxyde) will substracts the more acidic atom of hydrogen in the molecule. In the malonic ester, it would be the hydrogens from carbon 2.
2) Enolate alkylation. Once the enolate has been formed in the previous step, it will become a nucleophyle, and will attack the alkyl halide to form an enolate alkyl. Then, as we have excess of base, we are going back to step 1 to substract the remaining hydrogen, and then, step 2 again so the remaining bromine leaves the molecule. In this part, it will form the ring.
3) Ester hydrolisis. When the ring is formed, it's time to do an hydrolisis of the ester, so we can convert the ester into carboxilic acids. As we have two ester,we will have two carboxilic acids.
4) Decarboxilation. Finally, a decarboxilation occurs in presence of heat to have the final product with a ring and CO2 there as final products.
See picture attached for products thislllll
