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Phoenix [80]
3 years ago
5

The probability that you roll a two on a six-sided die is 1 6 16 . If you roll the die 60 times, how many twos can you expect to

roll
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

10 Twos

Step-by-step explanation:

One divided by six; 0.1667. Multiply that result by sixty to get  ten.

I know I'm late, but I thought I might answer it for my personal pleasure. lol :)

vodomira [7]3 years ago
6 0

Answer:

60 * 1/6 = 10

we can expect 10 times to roll the 2.

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Answer:

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Step-by-step explanation:

3 0
3 years ago
There was a triangle ABC with sides 15, 20, and 10. One of the sides of a triangle, which is similiar to ABC is 60. What are the
wlad13 [49]

Answer:

The possible pairs of sides are 90 and 120, 30 and 45, and 80 and 40.

Step-by-step explanation:

We know that 60 is a multiple of 15, 20, and 30, so we multiply by each factor to find all possible pairs: 10x6=60, 20x6=120, and 15x6=90, that gives your first pair, <u>90 and 120</u>.

We have now multiplied our first factor, 6. Now we need to multiply our second factor, 3: 20x3=60, 15x3=45, and 10x3=30. That gives your second pair, <u>30 and 45</u>.

Finally, we need to multiply by our 3rd factor, 4: 15x4=60, 20x4=80, and 10x4=40. That gives you your final possible pair, <u>80 and 40</u>.

I hope this helps :-)

3 0
3 years ago
Solve this system of equations by using the elimination method -2x-2y=-6, 3x+4y=8
adoni [48]

Step-by-step explanation:

- 2x-2y=-6

3x+4y=8

multiply equation (1) by 3 and equation (2) by 2

- 6x-6y=18

6x+8y=16

Add

2y=34

y= 34÷2

y=17

substitute 17 for y in equation (2)

3x+4y=8

3x+4(17)=8

3x+68=8

3x=8-68

3x=-60

x=-60÷3

x=-20

x=-20,y=17

8 0
3 years ago
Find x for,<br> sin⁻¹ 4x + sin⁻¹ 3x = -<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B2%7D" id="TexFormula1" title="\
Novay_Z [31]
<h2>Explanation:</h2><h2></h2>

Let's solve this problem graphically. Here we have the following equation:

sin^{-1}(4x) + sin^{-1}(3x) = -\frac{\pi}{2}

So we can rewrite this as:

f(x)=sin^{-1}(4x) + sin^{-1}(3x) \\ \\ g(x)= -\frac{\pi}{2}

So the solution to the equation is the x-value at which the functions f and g intersect. In other words:

f(x)=g(x) \\ \\ sin^{-1}(4x) + sin^{-1}(3x) = -\frac{\pi}{2}

Using graphing calculator, we get that this value occurs at:

\boxed{x=-0.2}

3 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
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