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Phoenix [80]
3 years ago
5

The probability that you roll a two on a six-sided die is 1 6 16 . If you roll the die 60 times, how many twos can you expect to

roll
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

10 Twos

Step-by-step explanation:

One divided by six; 0.1667. Multiply that result by sixty to get  ten.

I know I'm late, but I thought I might answer it for my personal pleasure. lol :)

vodomira [7]3 years ago
6 0

Answer:

60 * 1/6 = 10

we can expect 10 times to roll the 2.

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Q # 2 Graph TWX and it's image after a rotation of 90° counterclockwise about the origen
const2013 [10]
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T(3,4) ⇒⇒⇒ T'(-4,3)
W(-2,-1) ⇒⇒⇒ W'(1,-2)
x(-3,3) ⇒⇒⇒ x'(-3,-3)

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6 0
3 years ago
This.table represents a proportional relationship between x and y x 0 3 6 19
melamori03 [73]

Answer:

k = +4

Step-by-step explanation:

8 0
2 years ago
DONT ANSWER JUST FOR POINTS! PLEASE, PLEASE HELP ME! I NEED THE ANSWER! RIGHT AWAY! ILL GIVE MOST BRAINLIEST!
Nataliya [291]

Answer:

  • D. They are similar by the definition of similarity in terms of a dilation.

Step-by-step explanation:

<em>Refer to attached</em>

The points are plotted and connected to make triangles

As per the diagram, the triangles are similar, each side of ABC is reduced twice to make the corresponding sides of DEF, so the scale factor is 1/2.

<u>Correct choice is D</u>

  • They are similar by the definition of similarity in terms of a dilation.

6 0
2 years ago
Let n1=50​, X1=10​, n2=50​, and X2=30. Complete parts​ (a) and​ (b) below. a. At the 0.10 level of​ significance, is there evide
iren2701 [21]

Answer:

|Z| = |-4.089| > 1.645 at 0.10 level of significance

Null hypothesis is rejected at  0.10 level of significance

<em>There is a difference between the two Population proportions</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given first sample size (n₁)  = 50

Given  proportion of the first sample p⁻₁= 0.2

Given second sample size (n₂)  = 50

Given proportion of the second sample p₂⁻ = 30/50 = 0.6

<em>Null Hypothesis : H₀: p₁⁻=p₂⁻</em>

<em>Alternative Hypothesis : H₁: p₁⁻≠p₂⁻</em>

<u><em>Step(ii):-</em></u>

Z-statistic

             Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} } +\frac{1}{n_{2}) } } }

Where

         P = \frac{n_{1}p_{1} +n_{2}  p_{2} }{n_{1} +n_{2} }

        P = \frac{50X0.2+50X0.6}{50+50} = 0.4

<em>Z-statistic</em>

       

      Z = \frac{0.2-0.6}{\sqrt{0.4 X 0.6(\frac{1}{50}+\frac{1}{50}  } }

     Z =  -4.089

Level of significance =0.10

Z₀.₁₀ = 1.645

|Z| = |-4.089| > 1.645 at 0.10 level of significance

Null hypothesis is rejected at  0.10 level of significance

<u><em>Final answer</em></u>:-

<em>There is a difference between the two Population proportions</em>

   

     

       

3 0
2 years ago
Solve the system of equations: *
Vitek1552 [10]

Answer:

One solution: (6,0)

Step-by-step explanation:

4(6)+2(0)=24

6+0=6

6 0
3 years ago
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