Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
Derivitive of cosx=-sinx
dy/dx sinx=cosx
and use chain rue
2cosx=-2sinx
2cos2x=-4sin2x
so
-2sinx-4sin2x id the deritivitve
Answer:
The way to answer this question is to find out the price per pound potato by dividing the amount the restaurant chief paid by the number of pounds bought.
Your question lacks details on the pounds bought in the other stores so I will assume these figures and you can use it as a reference.
Restaurant B - 2 pounds
Restaurant C - 12 pounds
Restaurant D - 5 pounds
Price per pound
Restaurant A = 6.60/8
= $0.83
Restaurant B = 3.50/2
= $1.75
Restaurant C = 9.75/12
= $0.82
Restaurant D = 4.80/8
= $0.96
<u><em>Restaurant C </em></u><em>has the lowest price per pound for potatoes. </em>
Answer: 2
Have a good day ¯\_(ツ)_/¯
